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Drupady [299]
3 years ago
8

Solve the equations for x and match the solutions.

Mathematics
2 answers:
tino4ka555 [31]3 years ago
5 0

Answer:

Step-by-step explanation:

by putting 4=6/ax+5

Liono4ka [1.6K]3 years ago
3 0

Answer:

1. The solution of first equation is x=-\frac{a}{6}.

2. Therefore the solution of second equation is x=\frac{3}{a}.

3. The solution of third equation is x=-\frac{6}{a}.

Step-by-step explanation:

The first equation is

4=\frac{6}{a}x+5

Subtract 5 from both the sides.

4-5=\frac{6}{a}x+5-5

-1=\frac{6}{a}x

Multiply both sides by a.

-a=6x

Divide both sides by 6.

-\frac{a}{6}=x

Therefore the solution of first equation is x=-\frac{a}{6}.

The second equation is

7+2ax=13

Subtract 7 from both the sides.

7+2ax-7=13-7

2ax=6

Multiply both sides by 2a.

\frac{2ax}{2a}=\frac{6}{2a}

x=\frac{3}{a}

Therefore the solution of second equation is x=\frac{3}{a}.

The third equation is

-ax-20=-14

Add 20 on both the sides.

-ax-20+20=-14+20

-ax=6

Multiply both sides by -a.

x=-\frac{6}{a}

Therefore the solution of third equation is x=-\frac{6}{a}.

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coldgirl [10]

Answer:

a) 60% probability that the distance is environment friendly.

b) The mean of the distances between the telephone poles is 52.5 meters.

c) The standard deviation of the distance between the telephone poles is 7.22 meters.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X lower than x is given by the following formula.

P(X \leq x) = \frac{x - a}{b-a}

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60% probability that the distance is environment friendly.

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M = \frac{a + b}{2}

So

M = \frac{a + b}{2} = \frac{40 + 65}{2} = 52.5

c) Find the standard deviation of the distance between the telephone poles.

The standard deviation of the uniform distribution is:

S = \sqrt{\frac{(b-a)^{2}}{12}}

So

S = \sqrt{\frac{(65-40)^{2}}{12}} = 7.22

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3 years ago
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