1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Drupady [299]
3 years ago
8

Solve the equations for x and match the solutions.

Mathematics
2 answers:
tino4ka555 [31]3 years ago
5 0

Answer:

Step-by-step explanation:

by putting 4=6/ax+5

Liono4ka [1.6K]3 years ago
3 0

Answer:

1. The solution of first equation is x=-\frac{a}{6}.

2. Therefore the solution of second equation is x=\frac{3}{a}.

3. The solution of third equation is x=-\frac{6}{a}.

Step-by-step explanation:

The first equation is

4=\frac{6}{a}x+5

Subtract 5 from both the sides.

4-5=\frac{6}{a}x+5-5

-1=\frac{6}{a}x

Multiply both sides by a.

-a=6x

Divide both sides by 6.

-\frac{a}{6}=x

Therefore the solution of first equation is x=-\frac{a}{6}.

The second equation is

7+2ax=13

Subtract 7 from both the sides.

7+2ax-7=13-7

2ax=6

Multiply both sides by 2a.

\frac{2ax}{2a}=\frac{6}{2a}

x=\frac{3}{a}

Therefore the solution of second equation is x=\frac{3}{a}.

The third equation is

-ax-20=-14

Add 20 on both the sides.

-ax-20+20=-14+20

-ax=6

Multiply both sides by -a.

x=-\frac{6}{a}

Therefore the solution of third equation is x=-\frac{6}{a}.

You might be interested in
Grandma's recipe for sugar cookies 1 cups butter 2 cups sugar 4 eggs 1/2 teaspoon baking powder 1 1/4 cups of flower 1/4 teaspoo
olasank [31]
Thank you............?
6 0
3 years ago
Point A is plotted at (-5, 3)
Diano4ka-milaya [45]

Answer:

quadrant 1

Step-by-step explanation:

quadrant 1 is (-,+)

5 0
3 years ago
PLEAS HELP!!! Examine the graph.
raketka [301]
Similarly to the last graph that decreased, this one increases, so you have to see where the line points upwards into the right top corner
CD
7 0
3 years ago
Read 2 more answers
The side of one square is equal to 3m and its diagonal is equal to the side of a second square. Find the diagonal of the second
navik [9.2K]

Answer:

6m

Step-by-step explanation:

the side of first square = 3 m

area of first square = 3^2= 9 m^2

let the side of second square = x m

since diagonal of first square = x m as per the question

in a square each angle is 90 degree

therefore by applying pythagorus theorem ,

diagonal ^2 = side^2 + side ^2

diagonal^2 = 3^2+3^2=9+9

DIAGONAL= square root of 18

diagonal= 3\sqrt{2} m = side of second square

therefore in second square ,

one angle is 90  degree , therefore by applying pythagorue theorem

diaqonal^2 = side ^2 + side ^2 = (3\sqrt{2})^2 + ( 3\sqrt{2})^2

diagonal ^2 = 18 + 18

diagonal = square root of 36

therefore diagonal of second square is 6m

hope it helps you... please mark me as the brainliest..

8 0
3 years ago
Read 2 more answers
On weekends a movie ticket costs $10.50. form an inequality and solve it to find the maximum number of tickets kate can buy with
Greeley [361]

$10.50

10 Tickets would be $105.00

$105.00 - $10.50 = $94.50 so 9 Tickets would be $94.50

$105.00 + $94.50 = $199.50

$205.00 - $199.50 = $5.50 which isn't enough for another ticket.

10 Tickets + 9 Tickets = 19 Tickets.

3 0
2 years ago
Other questions:
  • I really need help plzzz
    14·1 answer
  • Sara wants to purchase a CD player for $115.99. She earns 5.25 per hour babysitting. If h represents the number of hours she bab
    5·1 answer
  • 4/5 of 40
    10·1 answer
  • How do you solve ¾ = 1/12 x + 2?
    9·1 answer
  • Find the value of ax 4 ; a = 2, x = 1. <br><br> Select one: a. 2 b. 4 c. 1 d. 8
    9·2 answers
  • Which is the graph of y=-x-3?
    8·1 answer
  • 3<br> 4× 20= <br> 3 × 20<br> 4 = <br><br><br> please help fast
    15·1 answer
  • 4. What is the mass of a truck if it produces a force of 14,000N while accelerating at a rate of
    13·1 answer
  • NEED NOW PLEASE.....
    15·1 answer
  • Which relationship has a zero slope?
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!