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3 years ago

Solve the equations for x and match the solutions.

Mathematics

2 answers:

tino4ka555 [31]3 years ago

5 0

Answer:

Step-by-step explanation:

by putting 4=6/ax+5

Liono4ka [1.6K]3 years ago

3 0

Answer:

1. The solution of first equation is $x=-\frac{a}{6}$ .

2. Therefore the solution of second equation is $x=\frac{3}{a}$ .

3. The solution of third equation is $x=-\frac{6}{a}$ .

Step-by-step explanation:

The first equation is

$4=\frac{6}{a}x+5$

Subtract 5 from both the sides.

$4-5=\frac{6}{a}x+5-5$

$-1=\frac{6}{a}x$

Multiply both sides by a.

$-a=6x$

Divide both sides by 6.

$-\frac{a}{6}=x$

Therefore the solution of first equation is $x=-\frac{a}{6}$ .

The second equation is

$7+2ax=13$

Subtract 7 from both the sides.

$7+2ax-7=13-7$

$2ax=6$

Multiply both sides by 2a.

$\frac{2ax}{2a}=\frac{6}{2a}$

$x=\frac{3}{a}$

Therefore the solution of second equation is $x=\frac{3}{a}$ .

The third equation is

$-ax-20=-14$

Add 20 on both the sides.

$-ax-20+20=-14+20$

$-ax=6$

Multiply both sides by -a.

$x=-\frac{6}{a}$

Therefore the solution of third equation is $x=-\frac{6}{a}$ .

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3 years ago

a trail mix recipe calls for 3/4 a cup of raisins for every 5/8 of a cup of peanuts. how mant peanuts will be needed for 1 cup o

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Answer:

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Step-by-step explanation

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3 years ago

A gas is said to be compressed adiabatically if there is no gain or loss of heat. When such a gas is diatomic (has two atoms per

Tems11 [23]

Answer:

The pressure is changing at $\frac{dP}{dt}=3.68$

Step-by-step explanation:

Suppose we have two quantities, which are connected to each other and both changing with time. A related rate problem is a problem in which we know the rate of change of one of the quantities and want to find the rate of change of the other quantity.

We know that the volume is decreasing at the rate of $\frac{dV}{dt}=-4 \:{\frac{cm^3}{min}}$ and we want to find at what rate is the pressure changing.

The equation that model this situation is

$PV^{1.4}=k$

Differentiate both sides with respect to time t.

$\frac{d}{dt}(PV^{1.4})= \frac{d}{dt}k\\$

The Product rule tells us how to differentiate expressions that are the product of two other, more basic, expressions:

$\frac{d}{{dx}}\left( {f\left( x \right)g\left( x \right)} \right) = f\left( x \right)\frac{d}{{dx}}g\left( x \right) + \frac{d}{{dx}}f\left( x \right)g\left( x \right)$

Apply this rule to our expression we get

$V^{1.4}\cdot \frac{dP}{dt}+1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}=0$

Solve for $\frac{dP}{dt}$

$V^{1.4}\cdot \frac{dP}{dt}=-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}\\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}}{V^{1.4}} \\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}$

when P = 23 kg/cm2, V = 35 cm3, and $\frac{dV}{dt}=-4 \:{\frac{cm^3}{min}}$ this becomes

$\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}\\\\\frac{dP}{dt}=\frac{-1.4\cdot 23 \cdot -4}{35}}\\\\\frac{dP}{dt}=3.68$

The pressure is changing at $\frac{dP}{dt}=3.68$ .

7 0

4 years ago

How do you factor this in the form (x+b)(x+c)

faust18 [17]

So you have your polynomial. To factor this out, you need to find the factors of -45 that will add up to 3. These two factors would be -5 and 8. So, you have factored your polynomial! (x-5)(x+8). If you are still unsure, simply use the FOIL method to check and see if you get the same polynomial back. Hope this helps!

7 0

3 years ago

A company made 13,450,000 in sales last year write this number in scientific notation

3241004551 [841]

Answer:

1.345*10^7

Step-by-step explanation:

Here we need to rewrite 13,450,000 in scientific notation, which looks like x.xx*10^n.

To move the decimal point in 13,450,000 to its proper place between the 3 and the 4, a move of 7 digits, we need to multiply 1.345 by 10^7.

13,450,000 in scientific notation is 1.345*10^7.

5 0

3 years ago