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jeka57 [31]
2 years ago
13

What is the solution set of the quadratic inequality x^2+x-2>0

Mathematics
2 answers:
wariber [46]2 years ago
7 0
The photo will explain

STatiana [176]2 years ago
3 0

Answer: (-∞, -2) U (1, ∞)

<u>Step-by-step explanation:</u>

    x² + x - 2 > 0

First, find the zeros by setting the equation EQUAL to zero:

   x² + x - 2 = 0

 (x + 2)(x - 1) = 0

x + 2 = 0    x - 1 = 0

  x = -2        x = 1

Next, choose a test point to the left, between, and to the right of the zeros and check to see if the test points are positive (greater than zero)

Left (x = -3):    (-3 + 2)(-3 - 1) = (-)(-) = +

Between (x = 0):   (0 + 2)(0 - 1) = (+)(-) = -

Right (x = 2):   (2 + 2)(2 - 1) = (+)(+) = +

**************************************************

The left and right test points are positive (greater than zero) so the solution is x < -2 and x > 1

Interval Notation: (-∞, -2) U (1, ∞)



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The measure of two complementary angles are in the ratio 1:4. What are the degree measures of the two angles ?
777dan777 [17]

Answer:

18,72

Step-by-step explanation:

Complementary angles add to 90 degrees

Multiply the ratio by x

1x+4x = 90

Combine like terms

5x = 90

divide by 5

5x/5 = 90/5

x =18

The first angle is 18 degrees

4*18 =72

The second angle is 72 degrees

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3 years ago
1. 4x + 5 + 7y + 3x *
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1/2(6 2/3+1/4)-5/24=
Helen [10]

For this case we must simplify the following expression:

\frac {1} {2} (6 \frac {2} {3} + \frac {1} {4}) - \frac {5} {24} =

We convert the mixed number to an improper fraction:

6 \frac {2} {3} = \frac {3 * 6 + 2} {3} = \frac {20} {3}

So, by rewriting we have:

\frac {1} {2} (\frac {20} {3} + \frac {1} {4}) - \frac {5} {24} =\\\frac {1} {2} (\frac {4 * 20 + 3 * 1} {4 * 3}) - \frac {5} {24} =\\\frac {1} {2} (\frac {80 + 3} {12}) - \frac {5} {24} =\\\frac {1} {2} (\frac {83} {12}) - \frac {5} {24} =

\frac {83} {24} - \frac {5} {24} =\\\frac {83-5} {24} =\\\frac {78} {24} =\\\frac {39} {12} =\\\frac {13} {4} =\\3 \frac {1} {4}

Answer:

3 \frac {1} {4}

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3 years ago
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