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jeka57 [31]
3 years ago
13

What is the solution set of the quadratic inequality x^2+x-2>0

Mathematics
2 answers:
wariber [46]3 years ago
7 0
The photo will explain

STatiana [176]3 years ago
3 0

Answer: (-∞, -2) U (1, ∞)

<u>Step-by-step explanation:</u>

    x² + x - 2 > 0

First, find the zeros by setting the equation EQUAL to zero:

   x² + x - 2 = 0

 (x + 2)(x - 1) = 0

x + 2 = 0    x - 1 = 0

  x = -2        x = 1

Next, choose a test point to the left, between, and to the right of the zeros and check to see if the test points are positive (greater than zero)

Left (x = -3):    (-3 + 2)(-3 - 1) = (-)(-) = +

Between (x = 0):   (0 + 2)(0 - 1) = (+)(-) = -

Right (x = 2):   (2 + 2)(2 - 1) = (+)(+) = +

**************************************************

The left and right test points are positive (greater than zero) so the solution is x < -2 and x > 1

Interval Notation: (-∞, -2) U (1, ∞)



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Your answer is x = 2.92 = 3.
To answer this question you need to use trigonometry, so the first step is to identify the hypotenuse, opposite, and adjacent.
Because the angle 73 is in the bottom corner next to the length x, we know that the length x is the adjacent. The length 10 is opposite the right angle so this must be the hypotenuse.
We know that cos(θ) = adjacent/hypotenuse, so we can substitute in what we know:
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5 0
3 years ago
Need help on this question i dont get it ima be posting some more but i need help on this on first
Anuta_ua [19.1K]

Answer:

The answer is B.

Step-by-step explanation:

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