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jeka57 [31]
2 years ago
13

What is the solution set of the quadratic inequality x^2+x-2>0

Mathematics
2 answers:
wariber [46]2 years ago
7 0
The photo will explain

STatiana [176]2 years ago
3 0

Answer: (-∞, -2) U (1, ∞)

<u>Step-by-step explanation:</u>

    x² + x - 2 > 0

First, find the zeros by setting the equation EQUAL to zero:

   x² + x - 2 = 0

 (x + 2)(x - 1) = 0

x + 2 = 0    x - 1 = 0

  x = -2        x = 1

Next, choose a test point to the left, between, and to the right of the zeros and check to see if the test points are positive (greater than zero)

Left (x = -3):    (-3 + 2)(-3 - 1) = (-)(-) = +

Between (x = 0):   (0 + 2)(0 - 1) = (+)(-) = -

Right (x = 2):   (2 + 2)(2 - 1) = (+)(+) = +

**************************************************

The left and right test points are positive (greater than zero) so the solution is x < -2 and x > 1

Interval Notation: (-∞, -2) U (1, ∞)



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<h3>What do you mean by standard deviation?</h3>

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