All categories

3 years ago

Which expression represents "6 more than x"?

Mathematics

2 answers:

gregori [183]3 years ago

7 0

Answer: x+6 is the answer you’re looking for! :)

zysi [14]3 years ago

6 0

Answer:

x+6

Step-by-step explanation:

You might be interested in

Oi lend a hand here? Math isn't my thing :P

Leni [432]

x is less than or equal to 5, really simple

8 0

3 years ago

Read 2 more answers

Using the Breadth-First Search Algorithm, determine the minimum number of edges that it would require to reach

jekas [21]

Answer:

The algorithm is given below.

#include <iostream>

#include <vector>

#include <utility>

#include <algorithm>

using namespace std;

const int MAX = 1e4 + 5;

int id[MAX], nodes, edges;

pair <long long, pair<int, int> > p[MAX];

void initialize()

{

for(int i = 0;i < MAX;++i)

id[i] = i;

}

int root(int x)

{

while(id[x] != x)

{

id[x] = id[id[x]];

x = id[x];

}

return x;

}

void union1(int x, int y)

{

int p = root(x);

int q = root(y);

id[p] = id[q];

}

long long kruskal(pair<long long, pair<int, int> > p[])

{

int x, y;

long long cost, minimumCost = 0;

for(int i = 0;i < edges;++i)

{

// Selecting edges one by one in increasing order from the beginning

x = p[i].second.first;

y = p[i].second.second;

cost = p[i].first;

// Check if the selected edge is creating a cycle or not

if(root(x) != root(y))

{

minimumCost += cost;

union1(x, y);

}

return minimumCost;

}

int main()

{

int x, y;

long long weight, cost, minimumCost;

initialize();

cin >> nodes >> edges;

for(int i = 0;i < edges;++i)

{

cin >> x >> y >> weight;

p[i] = make_pair(weight, make_pair(x, y));

}

// Sort the edges in the ascending order

sort(p, p + edges);

minimumCost = kruskal(p);

cout << minimumCost << endl;

return 0;

}

8 0

3 years ago

Standard form............

umka2103 [35]

Standard form is using only numerical values (numbers.)

Ninety-eight = 98
six-tenth = 0.6

98 + 0.6 = 98.6

98.6 is your answer

Hope this helps

8 0

3 years ago

Need help ASAP !!!<br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B95%20%5Ctimes%2019%20%5Ctimes%205%7D%20" id="TexFormula

dimulka [17.4K]

Answer:

the answer is 9025

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Find the 95% confidence interval for estimating the population mean μ

AVprozaik [17]

We first need to determine whether we are dealing with means or proportions in this problem. Since we are given the sample and population mean, we know that we are dealing with means.

Since we have one sample mean, this means we are creating a confidence interval for one sample (1 Samp T Int).

Normally we would check for conditions, but since this is not formulated as a "real-world scenario" type problem, it is hard to check for randomness and independence. Therefore, I will be excluding conditions from this answer.

<h3>Confidence Interval Formula</h3>

The formula for constructing a <u>confidence interval for means</u> is as follows: