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Bad White [126]
3 years ago
8

If the exterior angle of a regular octagon measures 11x + 1 what is the value of x?

Mathematics
1 answer:
Basile [38]3 years ago
8 0

Answer:

x = 4

Step-by-step explanation:

The exterior angles of an octagon equal 45 degrees. So if the angles are 11x+1, set it equal to 45 and solve for x.

11x+1 = 45

11x = 44

x= 4

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Write the slope-intercept form of the equation of the line that is parallel to AB and passes through Point X. Show all
DanielleElmas [232]

find y=mx+b for line parallel to AB.

The line that is parallel will have the same slope as line AB:

the slope of line AB is

m=(8-3)/(-10-2)

=5/-12

=-5/12

Since the line going through X is parallel the vertical distance of the new line to AB is the same for all values of the domain(x-axis).

at x=-5 the point X has the y value of 10 which is 4 more than the y value for AB based on the graph.

To find the intercept b of the line going through X that is parallel to AB we just add 4 to the intercept of AB, which is 4 so

4+4=8

7 0
2 years ago
Adrianna sold her DVD that cost $20 with an 8% markup. How much did Adrianna make with the 8% markup?
djverab [1.8K]
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20 x 0.01 = $0.20
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5 0
3 years ago
What is the cross-sectional area of a cement pipe 2 in. thick with an inner diameter of 5 ft? Use pie 3.14.
Paul [167]

Answer:

1.60 ft^{2}

Step-by-step explanation:

Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.

i.e Area = \pir^{2}

So that,

for the inner part of the pipe,

r = \frac{diameter}{2}

 = \frac{5}{2}

 = 2.5 feet

Area of the inner part of the pipe = \pir^{2}

                                 = 3.14 x (2.5)^{2}

                                 = 19.625

Are of the inner part of the pipe is 19.63 ft^{2}.

Total diameter of the pipe = 5 + 0.2

                                           = 5.2 feet

r = \frac{5.2}{2}

 = 2.6 feet

Area of the pipe = \pir^{2}

                            = 3.14 x (2.6)^{2}

                            = 21.2264

Area of the pipe is 21.23 ft^{2}.

Thus the cross sectional area = Area of the pipe - Area of the inner part of the pipe

                                           = 21.2264 - 19.625

                                           = 1.6014

The cross sectional area of the cement pipe is 1.60 ft^{2}.

6 0
2 years ago
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