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STatiana [176]
2 years ago
13

When driving in England, a U.S. tourist puts gasoline in his car and pays 1.35 European pounds per liter (pounds per liter). The

price of gasoline in his U.S. hometown is $3.39 per gallon. Suppose the exchange rate is 0.705 pounds for $1.50. Is gasoline more expensive in England or in the U.S.?
Mathematics
1 answer:
Eddi Din [679]2 years ago
5 0

Answer:  England

<u>Step-by-step explanation:</u>

England: 1.35 euro/liter

\text{U.S:}\quad \dfrac{\$3.39}{gallon}\times \dfrac{0.705\ euro}{\$1.50}\times \dfrac{1\ gallon}{3.785\ liter}=\dfrac{0.42\ euro}{liter}

     1.35 > 0.42

England > US

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2 years ago
Given that f.x 3x-2 over x+1 g[x] x +5 evaluate f[-4] and gf [-2]
Jobisdone [24]

The value of f[ -4 ] and g°f[-2] are \frac{14}{3} and 13 respectively.

<h3>What is the value of f[-4] and g°f[-2]?</h3>

Given the function;

  • f(x) = \frac{3x-2}{x+1}
  • g(x)=x+5
  • f[ -4 ] = ?
  • g°f[ -2 ] = ?

For f[ -4 ], we substitute -4 for every variable x in the function.

f(x) = \frac{3x-2}{x+1}\\\\f(-4) = \frac{3(-4)-2}{(-4)+1}\\\\f(-4) = \frac{-12-2}{-4+1}\\\\f(-4) = \frac{-14}{-3}\\\\f(-4) = \frac{14}{3}

For g°f[-2]

g°f[-2] is expressed as g(f(-2))

g(\frac{3x-2}{x+1}) =  (\frac{3x-2}{x+1}) + 5\\\\g(\frac{3x-2}{x+1}) =  \frac{3x-2}{x+1} + \frac{5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{3x-2+5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{8x+3}{x+1}\\\\We\ substitute \ in \ [-2] \\\\g(\frac{3x-2}{x+1}) =  \frac{8(-2)+3}{(-2)+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{-16+3}{-2+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{-13}{-1}\\\\g(\frac{3x-2}{x+1}) =  13

Therefore, the value of f[ -4 ] and g°f[-2] are \frac{14}{3} and 13 respectively.

Learn more about composite functions here: brainly.com/question/20379727

#SPJ1

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1 year ago
PLEASE HELP ME WITH THIS!! ;(
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Zoom in and mark me as brainliest

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2 years ago
Giving 97 points for answer. Need asap for a, b, and c pls help.
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sabi 97 tas 49 lang amp ginagawa mo

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