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Georgia [21]
3 years ago
7

The diameter of a tennis ball is 2 cm and the diameter of the softball is 1 cm. About how many times as

Mathematics
1 answer:
zmey [24]3 years ago
4 0

Step-by-step explanation:

It is given that,

The diameter of a tennis ball is 2 cm and the diameter of the softball is 1 cm. So, radius of tennis ball is 1 cm and radius of softball is 0.5 cm.

Both balls are in the shape of sphere. Half of the balls will becomes hemisphere. The surface area of hemisphere is given by :

A=2\pi r^2

Taking ratio of both balls, i.e.

\dfrac{A_1}{A_2}=\dfrac{r_1^2}{r_2^2}

\dfrac{A_t}{A_s}=\dfrac{r_t^2}{r_s^2}\\\\\dfrac{A_t}{A_s}=\dfrac{1^2}{(0.5)^2}\\\\\dfrac{A_t}{A_s}=4

So, the surface area of a half of the tennis ball is 4 times of he surface area of a half of the softball.

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Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

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<u>Algebra I</u>

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Step-by-step explanation:

<u>Step 1: Define</u>

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Step-by-step explanation:

Las cosas que se pueden contar (i.e. Contar y clasificar frutas) así como cosas que se pueden dividir se pueden medir en fracciones (i.e. Cortar un pastel), mientras que las cosas que no se pueden contar, de naturaleza no discreta, así como cosas que no se pueden dividir (i.e. Líquidos, material granulado) se pueden medir en decimales.

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