Question

The diameter of a tennis ball is 2 cm and the diameter of the softball is 1 cm. About how many times as

Answer 1

Step-by-step explanation:

It is given that,

The diameter of a tennis ball is 2 cm and the diameter of the softball is 1 cm. So, radius of tennis ball is 1 cm and radius of softball is 0.5 cm.

Both balls are in the shape of sphere. Half of the balls will becomes hemisphere. The surface area of hemisphere is given by :

$A=2\pi r^2$

Taking ratio of both balls, i.e.

$\dfrac{A_1}{A_2}=\dfrac{r_1^2}{r_2^2}$

$\dfrac{A_t}{A_s}=\dfrac{r_t^2}{r_s^2}\\\\\dfrac{A_t}{A_s}=\dfrac{1^2}{(0.5)^2}\\\\\dfrac{A_t}{A_s}=4$

So, the surface area of a half of the tennis ball is 4 times of he surface area of a half of the softball.