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Georgia [21]
3 years ago
7

The diameter of a tennis ball is 2 cm and the diameter of the softball is 1 cm. About how many times as

Mathematics
1 answer:
zmey [24]3 years ago
4 0

Step-by-step explanation:

It is given that,

The diameter of a tennis ball is 2 cm and the diameter of the softball is 1 cm. So, radius of tennis ball is 1 cm and radius of softball is 0.5 cm.

Both balls are in the shape of sphere. Half of the balls will becomes hemisphere. The surface area of hemisphere is given by :

A=2\pi r^2

Taking ratio of both balls, i.e.

\dfrac{A_1}{A_2}=\dfrac{r_1^2}{r_2^2}

\dfrac{A_t}{A_s}=\dfrac{r_t^2}{r_s^2}\\\\\dfrac{A_t}{A_s}=\dfrac{1^2}{(0.5)^2}\\\\\dfrac{A_t}{A_s}=4

So, the surface area of a half of the tennis ball is 4 times of he surface area of a half of the softball.

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