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4 years ago

Evaluate: 5 - 3 x when x = - 7

Mathematics

2 answers:

skad [1K]4 years ago

7 0

5-3x-7

the answer is -14

tamaranim1 [39]4 years ago

3 0

5 - 3 x
= 5 - 3 (-7)
= 5 + 21
= 26

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HELP PLEASE 3. A child swims 50 yards in 50 seconds. How many FEET can she swim per second?

qaws [65]

Answer:

the answer should be two

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3 years ago

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Melissa buys a 10-pound box of apples. The box has 32 apples that are all identical. What is the weight of each apple in ounces?

Shalnov [3]

Answer:

Each apple weighs 5 ounces.

Step-by-step explanation:

This question can be solved using rules of three.

Each pound has 16 ounces.

So a 10-pound box will have 16*10 = 160 ounces

The box has 32 apples that are all identical. What is the weight of each apple in ounces?

So 32 apples have 160 ounces. How much does each apple weighs?

32 apples - 160 ounces

1 apple - x ounces

$32x = 160$

$x = \frac{160}{32}$

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4 years ago

Given that lim x → 2 f ( x ) = 1 lim x → 2 g ( x ) = − 4 lim x → 2 h ( x ) = 0 limx→2f(x)=1 limx→2g(x)=-4 limx→2h(x)=0, find the

VashaNatasha [74]

Answer:

According what I can read, I have the following statements:

$\lim_{x \to 2} f(x) = 1$

$\lim_{x \to 2} g(x) = -4$

$\lim_{x \to 2} h(x) = 0$

a) Applying properties of limits

$\lim_{x \to 2} f(x) + 5g(x) = \lim_{x \to 2} f(x) + 5 \lim_{x \to 2} g(x) = 1 + 5*-4 = -19$

b) Applying properties of limits

$\lim_{x \to 2} g(x)^{3} = {(\lim_{x \to 2} g(x))}^{3} = (-4)^{3} = -64$

c) Applying properties of limits

$\lim_{x \to 2} \sqrt{f(x)} = \sqrt{\lim_{x \to 2} f(x)} = \sqrt{1} = 1$

d) Applying properties of limits

$\lim_{x \to 2} 4*g(x)*f(x) = 4*\lim_{x \to 2} g(x)*\lim_{x \to 2} f(x) = 4*-4*1 =-16$

e) Applying properties of limits

$\lim_{x \to 2} g(x)*h(x) = \lim_{x \to 2} g(x)*\lim_{x \to 2} h(x) = -4*0 =0$

f) Applying properties of limits

$\lim_{x \to 2} g(x)*h(x)*f(x) = \lim_{x \to 2} g(x)*\lim_{x \to 2} h(x)*\lim_{x \to 2} f(x = -4*0*1 =0$

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4 years ago

Two points A and B are on opposite sides of a building. A surveyor selects a third point C to place a transit. Point C is 52 fee

alexdok [17]

Answer:

Step-by-step explanation:1.

Use law of cosine.

AB^2 = AC^2 + BC^2 - 2 * AC * BC * cos(angle ACB)

AB^2 = 53^2 + 71^2 - 2(53)(71)cos(53)

Using calculator,

AB = about 57.6259 feet

Law of cosine again.

d^2 = 400^2 + 90^2 - 2(400)(90)cos(45)

using calculator,

d = about 342.3278 feet

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4 years ago

Please help me I don't understand (Algebra)

AlekseyPX

Answer:

3 adult tickets, 2 senior tickets, and 6 children's tickets

Step-by-step explanation:

Start by writing down the information they give you: they purchased 3 more children's tickets than adult tickets, 1 less senior ticket than adult tickets, total cost of $131. Now take all of that, and translate it into math terms.

3 more children's tickets than adult tickets can be represented by an expression like 3 + a, where a = adult tickets. 3 + a will give you the number of children tickets purchased.

1 less senior ticket than adult tickets can be written like a - 1, the number of adult tickets minus 1 because 1 less senior ticket was purchased.

Now, adult tickets cost $15, senior tickets cost $13, and children cost $10.

So now we can put together an equation like this:

10(3 + a) + 15(a) + 13(a - 1) = 131 ... that is, the number of children's tickets, 3 + a, times the cost of those tickets, 10, plus the number of adult tickets, a, times the cost of those tickets, 15, plus the number of senior tickets, a - 1, plus the cost of senior tickets, 13. From here, you just want to simplify.

30 + 10a + 15a + 13a - 13 = 131 ... multiply and distribute

38a + 17 = 131

38a = 114

a = 3

So they purchased 3 adult tickets.

Now that you know how many adult tickets you bought, you know that the number of senior tickets is the adults minus 1. So there were 2 senior tickets purchased. And since you know the number of adults tickets is 3, and that the number of children's tickets was three times the amount of adult tickets, then you know they bought tickets for 9 children because 3 + a = 3 + 3 = 6.

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4 years ago