Question

Write a quadratic equation in standard form that has two solutions, -10 and 3

Answer 1

 

$\displaystyle\bf\\\\x_1=-10~~and~~x_2=3\\\\(x-x_1)(x-x_2)=0\\\\(x-(-10))(x-3)=0\\\\(x+10)(x-3)=0\\\\x^2+10x-3x -30=0\\\\\boxed{\bf x^2+7x - 30=0}$