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3 years ago

Write a quadratic equation in standard form that has two solutions, -10 and 3

1 answer:

7 0

$\displaystyle\bf\\\\x_1=-10~~and~~x_2=3\\\\(x-x_1)(x-x_2)=0\\\\(x-(-10))(x-3)=0\\\\(x+10)(x-3)=0\\\\x^2+10x-3x -30=0\\\\\boxed{\bf x^2+7x - 30=0}$

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A forest covers 72,000 acres. A survey finds that 0.7% of the forest is old-growth trees. How many acres of old-growth trees

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3 years ago

Joanna is driving 185 miles to visit her family. She drives 68 miles in the morning, stops for lunch, and then drives the rest o

blondinia [14]

Answer:

I believe the answer is A. m + 68 = 185; m = 117

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

How to solve n-5*2/3=3/4

Scorpion4ik [409]

$n-5\cdot\dfrac{2}{3}=\dfrac{3}{4}\\\\n-\dfrac{10}{3}=\dfrac{3}{4}\ \ \ \ |\cdot12\\\\12n-12\cdot\dfrac{10}{3}=12\cdot\dfrac{3}{4}\\\\12n-4\cdot10=3\cdot3\\\\12n-40=9\ \ \ \ |+40\\\\12n=49\ \ \ \ \ |:12\\\\n=\dfrac{49}{12}$

5 0

4 years ago

Question 5 (5 points)

Tpy6a [65]

Answer:

The solution of the system of equations is, (1,-1,2)

Step-by-step explanation:

Given system equation;

x + 5y - 3z = -10

-5x + 6y – 5z = -21

-x + 8y - 8z = -25

Matrix form is written as;

$\left[\begin{array}{ccc}1&5&-3\\-5&6&-5\\-1&8&-8\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] = \left[\begin{array}{ccc}-10\\-21\\-25\end{array}\right] \\\\\\det. = 1\left[\begin{array}{cc}\\6&-5\\8&-8\end{array}\right] -5\left[\begin{array}{cc}\\-5&-5\\-1&-8\end{array}\right] -3\left[\begin{array}{cc}\\-5&6\\-1&8\end{array}\right] \\\\\\det. = 1(-8) -5(35)-3(-34)= -8 - 175+ 102 = -81$

Cofactor;

$First \ row \left[\begin{array}{cc}+\\ 6&-5\\\ 8&-8\end{array}\right \left\begin{array}{cc}-\\ -5&-5\\-1&-8\end{array}\right \left\begin{array}{cc}+\\-5&6\\-1&8\end{array}\right] = [-8 \ \ -35 \ \ -34]\\\\\\\ Second \ row \left[\begin{array}{cc}-\\ 5&-3\\\ 8&-8\end{array}\right \left\begin{array}{cc}+\\ 1&-3\\-1&-8\end{array}\right \left\begin{array}{cc}-\\1&5\\-1&8\end{array}\right] = [16\ \ -11 \ \ -13]\\\\\\$

$Third \ row \left[\begin{array}{cc}+\\ 5&-3\\\ 6&-5\end{array}\right \left\begin{array}{cc}-\\ 1&-3\\-5&-5\end{array}\right \left\begin{array}{cc}+\\1&5\\-5&6\end{array}\right]= [-7 \ \ 20\ \ 31]$

$Cofactor =$ $\left[\begin{array}{ccc}-8&-35&-34\\16&-11&-13\\-7&20&31\end{array}\right]$

$inverse \ matrix =-\frac{1}{81} \left[\begin{array}{ccc}-8&16&-7\\-35&-11&20\\-34&-13&31\end{array}\right] \\\\\\$

Solution of the matrix:

$\left[\begin{array}{c}x\\y\\z\end{array}\right] = -\frac{1}{81} \left[\begin{array}{ccc}-8&16&-7\\-35&-11&20\\-34&-13&31\end{array}\right] X \left[\begin{array}{c}-10\\-21\\-25\end{array}\right] = \left[\begin{array}{c}\frac{-8*-10 }{-81 } +\frac{16*-21 }{-81 } + \frac{-7*-25 }{-81 }\\\\\frac{-35*-10 }{-81 } +\frac{-11*-21 }{-81 }+ \frac{20*-25 }{-81 }\\\\\frac{-34*-10 }{-81 }+ \frac{-13*-21 }{-81 }+ \frac{31*-25 }{-81 }\end{array}\right] \\\\\$

$\left[\begin{array}{c}x\\y\\z\end{array}\right] = \left[\begin{array}{c}\frac{-81}{-81} \\\\\frac{81}{-81} \\\\\frac{-162}{-81} \end{array}\right] = \left[\begin{array}{c}1\\-1\\2\end{array}\right]$

Therefore, the correct option is (1,-1,2)

5 0

3 years ago

Ella has $50,000 is a saving account. The savings collect interest at an 8% annual rate that compounds every year. How much mone

Arturiano [62]

Answer:

210000$

Step-by-step explanation:

1st we find the SI which will be P*R*T/100=50000*8*5/100

=32000

32000 will be added per year

32000*5=160000 for 5 years

160000+50000=210000$

5 0

3 years ago