Answer:
Solution given:
for second
we have
f(x)=x²-9x-36
let
y=x²-9x-36
when
x=0
y=-36
when
y=0
0=x²-9x-36
x²-12x+3x-36=0
x(x-12)+3(x-12)=0
(x-12)(x+3)=0
either
x=12
x=-3
So,
x and y intercepts are (-3,0)(12,0) and 0,-36)
X/3 -2 = 5x-2 (multiply by 3)
x-6=15x-6
x=15x
14x=0
x=0
I think the answer will be t=2/3 or t= -2/3
First set up the equation to find answer: y=7-x. Then add it to the variable. 3x-1(7-x)=1. So that makes it 3x+-7+-1=1. Add like terms -7+-1=-8, so 3x+-8=1. Now to find x just switch the 8 to the other side. So you end up with 3x=9 since when you take away a number from one side you need to use the opposite value so adding 8 to -8 will cancel it out, then add it to the other, then just divide. 9/3=3, from here just substitute to find y. y=7+3. y=10.
The answer is x=2 and y=5. I hope I helped!
Answer:
Step-by-step explanation:
x-11