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Ratling [72]
3 years ago
13

What is the answer for this

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
5 0

Parallelogram

Area: 24m²

Perimeter: 26m

Trapezoid

Area:21cm²

Perimeter:22.6cm

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The following equation is true for all real values of k for which the expression on the left is defined, and A
Brut [27]

Answer:

A = 6k(k + 6)

Step-by-step explanation:

We have to solve the given equation for the value of A,

\frac{6k^2-36k}{A}.\frac{k^2+12k+36}{k^2-36}=1

\frac{(6k^2-36k)(k^2+12k+36)}{A(k^2-36)}=1

(6k² - 36k)(k² + 12k + 36) = A(k² -36)

6k(k - 6)(k + 6)² = A(k - 6)(k + 6)

A = \frac{6k(k-6)(k+6)^2}{(k-6)(k+6)}

A = 6k(k + 6)

Therefore, value of A is 6k(k + 6).

3 0
3 years ago
Is median a measure of center or a measure of variation
Marianna [84]

Answer:

a

Step-by-step explanation:

7 0
2 years ago
Given to
zheka24 [161]

Answer:

Step-by-step explanation:

Given:

\frac{AD}{DC}=\frac{BE}{EC}

To Prove:

AB║DE

Solution:

Since, corresponding sides of ΔACB and ΔDCE are proportional,

\frac{AD}{DC}=\frac{BE}{EC}

Both the triangles will be similar.

ΔACB ~ ΔDCE [By SAS property of similarity]

Therefore, ∠1 ≅ 2 [CPCTC]

Since, ∠1 and ∠2 are the corresponding angles

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7 0
3 years ago
Please Help! Look at Screenshot for question.
iogann1982 [59]

Answer:

C

Step-by-step explanation:

A modified box plot does not include the outliers in the whiskers, instead they are points outside of the whiskers

5,25,33,34,34,37,37,40,42,45,45,46,46,49,73

This data has 2 outliers 5 and 73 so we have 2 choices for a modified box plot D or D

The lowest value outside of the outliers is 25 , so C would be the logical choice

D has the lower end of the whisker too close to the outlier

3 0
3 years ago
Find the slope of the line that goes through (-4,5) and (3,-1)
scZoUnD [109]
Slope = (-1 - 5)/(3 + 4) = -6/7

answer
-6/7
4 0
3 years ago
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