Assuming that the actual question reads lines b and c are perpendicular to line d
we are given that c is perpendicular to line d and parallel to line a. Since b is also perpendicular to line d, a b and c must all be parallel (draw it out will make a lot more sense)
So b is also parallel to line a
Answer:
(-3, -2)
Step-by-step explanation:
To find the solution of two functions, you need to know at which x and y value they are equal. So solve for x and y when 1/3x - 1 = 2x + 4
1/3x - 1 = 2x + 4
First, subtract 2x from both sides.
-5/3x - 1 = 4
Add one to both sides.
-5/3x = 5
Multiply both sides by the reciprocal of -5/3 (3/-5)
x = -3
Then, substitute x into one of the equations to get y.
1/3(-3) - 1
-1 - 1 = -2
So drag the dot to the point (-3, -2)
Answer:
Any c answer that fits 5
<c<37 is correct.
Step-by-step explanation:
Say the three sides of the triangle are
a
,
b
and
c
. Here,
a
=
16
and
b
=
21
. We must find the possible values of
c
.
Since
a
+
c
>
b
, we can input:
16
+
c
>
21
c
>
5
.
So the lower bound of
c
is everything above
5
.
We also know that
a
+
b
>
c
. Inputting:
16
+
21
>
c
37
>
c
.
So
c
must be less than, but not including
37
.
In conclusion, the side length
c
must satisfy the following inequality:
Rational function:
A rational function is any function which can be defined by a rational fraction,
that is an algebraic fraction such that both the numerator and the denominator are polynomials
Let's assume
numerator polynomial is p(x)
denominator polynomial is q(x)
so, we can write rational function as
now, we will check each options
option-A:
we know that
we always get hole from rational function only
For exp:
Here , hole is at x=3
so, this is TRUE
option-B:
rational functions can not have irrational numbers
because we have both numerator and denominators are polynomial
so, this is FALSE
option-C:
We can get slant asymptote from rational function
For exp:
Here , slant line is y=x-3
so, this is TRUE
option-D:
Rational functions can have axis of symmetry
so, this is TRUE