The point that the graphs of f and g have in common are (1,0)
<h3>How to get the points?</h3>
The given functions are:
f(x) = log₂x
and
g(x) = log₁₀x
We know that logarithm of 1 is always zero.
This means that irrespective of the base, the y-values of both functions will be equal to 0 at x=1
Therefore the point the graphs of f and g have in common is (1,0).
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Answer:
×= 2 this is what I got as a result to my equations
Answer:
16 I guess.
Step-by-step explanation:
lolololololol?
Answer:
983040
Step-by-step explanation:
Second Year : 15x4=60
Third Year : 60x4=240
Fourth Year : 240x4=960
Fifth Year : 960x4=3840
Sixth Year : 3840x4=15360
Seventh Year : 15360x4 = 61440
Eighth Year: 61440x4=245760
Ninth Year : 245760x4= 983040
Answer:
14/3
Step-by-step explanation:
Simplify the following:
48/6 - 10/3
Hint: | Reduce 48/6 to lowest terms. Start by finding the GCD of 48 and 6.
The gcd of 48 and 6 is 6, so 48/6 = (6×8)/(6×1) = 6/6×8 = 8:
8 - 10/3
Hint: | Put the fractions in 8 - 10/3 over a common denominator.
Put 8 - 10/3 over the common denominator 3. 8 - 10/3 = (3×8)/3 - 10/3:
(3×8)/3 - 10/3
Hint: | Multiply 3 and 8 together.
3×8 = 24:
24/3 - 10/3
Hint: | Subtract the fractions over a common denominator to a single fraction.
24/3 - 10/3 = (24 - 10)/3:
(24 - 10)/3
Hint: | Subtract 10 from 24.
| 2 | 4
- | 1 | 0
| 1 | 4:
Answer: 14/3
