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Fed [463]
3 years ago
15

What is 8 lb. 12 oz. − 5 lb. 5 oz. ?

Mathematics
2 answers:
Novosadov [1.4K]3 years ago
8 0
3 pounds and 7 oz. is the awnswer
marysya [2.9K]3 years ago
7 0
3 7 is the answer I hope this helps
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Solve the inequality. <br><br>A. x ≤ -3<br><br>B. x ≥ -3<br><br>C. x ≤ 3<br><br>D. x ≥ 3
8090 [49]

Answer:

C

Step-by-step explanation:

7 0
3 years ago
When the volume of a gas is
Fudgin [204]

Answer: The initial volume is 593.76mL

Step-by-step explanation:

As you do not say anithing about the pressure, i guess that the pressure remains constant.

If the gas is an ideal gas, we have:

P*V = n*R*T

where P is pressure, n is number of moles and R is a constant.

Now, initially we have:

P*Vi = n*R*315°C

finally we have:

P*825mL = n*R*452°C

Now we can take the quiotient of those two equations and get:

(P*Vi)/(P*852mL) = (n*R*315°C)/( n*R*452°C)

Now we have:

Vi/852mL = 315/452

Vi =  (315/452)*852mL = 593.76mL

So when we expand the gas at constant pressure, we increase the temperature.  

3 0
3 years ago
Which two polygons is this polygon subdivided into?
marysya [2.9K]

Answer:

no diagram

Step-by-step explanation:

8 0
2 years ago
What is 2/9 divided by negative 6/5
Lerok [7]
The answer to your question is 5/27
4 0
3 years ago
Read 2 more answers
2x^3-x^2+x-2 factorize​
bekas [8.4K]

Answer:

(x-1)(2x^2+x+2)

Step-by-step explanation:

Factorize:

f(x)=2x^3-x^2+x-2

<u>Factor Theorem</u>

If f(a) = 0 for a polynomial then (x - a) is a factor of the polynomial f(x).

Substitute x = 1 into the function:

\implies f(1)=2(1)^3-1^2+1-2=0

Therefore, (x - 1) is a factor.

As the polynomial is cubic:

\implies  f(x)=(x-1)(ax^2+bx+c)

Expanding the brackets:

\implies  f(x)=ax^3+bx^2+cx-ax^2-bx-c

\implies  f(x)=ax^3+(b-a)x^2+(c-b)x-c

Comparing coefficients with the original polynomial:

\implies ax^3=2x^3 \implies a=2

\implies (b-a)x^2=-x^2 \implies b-2=-1 \implies b=1

\implies -c=-2 \implies c=2

Therefore:

\implies  f(x)=(x-1)(2x^2+x+2)

Cannot be factored any further.

4 0
2 years ago
Read 2 more answers
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