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GREYUIT [131]
1 year ago
11

A rectangular garden has a walkway around it. The area of the garden is 6(6.5x + 2.5). The combined area of the garden and the w

alkway is 6.5(8x + 6). Find the area of the walkway around the garden as the sum of two terms.
Mathematics
1 answer:
Rasek [7]1 year ago
7 0

According to the information given in the exercise, the following expression represents the area of the rectangular garden:

6\mleft(6.5x+2.5\mright)

And the following expression represents the combined area of the walkway around the rectangular garden and the area of the garden:

6.5\mleft(8x+6\mright)

You can identify that the word "combined" indicates that that expression was obtained by adding both areas.

Knowing the above, you can set up the following equation:

6(6.5x+2.5)+A=6.5(8x+6)

Where "A" is the area of the walkway around the rectangular garden.

Solving for "A", you get the following expression:

\begin{gathered} A=6.5(8x+6)-6(6.5x+2.5) \\ A=52x+39-39x-15 \\ A=13x+24 \end{gathered}

The answer is:

13x+24

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Solve -1/3w -3/5 = 1/5w
Dmitrij [34]

Answer:

w= -9/8

Step-by-step explanation:

-1/3w -3/5 = 1/5w

+1/3w            +1/3 w

-3/5=1/5w+1/3w

Make common denominators to combine like terms of the right

-3/5=1/5w+1/3w

         *3       *5

-3/5=3/15w+5/15w

-3/5=8/15w

multiply both sides by the reciprocal of 8/15 which is 15/8

-3/5*15/8=8/15w*15/8

\frac{-3}{5}*\frac{15}{8} ----> cross reduce 5 in the denominator becomes 1 and 15 in the numerator becomes 3

\frac{-3}{1}*\frac{3}{8} -----> now multiply across

w= -9/8

7 0
3 years ago
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the length of a rectangle is four times its width. the rectangle has an area of 1024cm^2 work out the width of the rectangle
olga2289 [7]
The width is 16 so the length is 64  (TO clarify W=16)

Hope this helps :)
7 0
3 years ago
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Evacuate the following using suitable identities (102)^3
snow_lady [41]

The value of (102)^3 exists 1061208.

<h3>How to estimate the value of (102)^3?</h3>

Let us rewrite (102)^3 as (100+2)^3

Now utilizing the identity (a+b)^3=a^3+b^3+3ab(a+b), we get

a = 100 and b = 2 then substitute the values of a and b then

(100+2)^3=100^3+2^3+[(3\times100\times2)(100+2)]

= 1000000 + 8 + (600 × 102)

= 1000000 + 8 + 61200

= 1061208

Hence, (102)^3=1061208

Therefore, the value of (102)^3 exists 1061208.

To learn more about cubic polynomial equation refer to:

brainly.com/question/28181089

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2 years ago
It is impossible to create a square pyramid by rotating a shape about an axis because its base is not ________.
natta225 [31]
It is impossible because it's base is not circular. A solid of revolution is <span>obtained by rotating a </span>plane curve<span> around some </span>straight line, that is, <span>the </span>axis of revolution that lies on the same plane. The closest to a square pyramid applying this concept is by rotating a right triangle around the opposite or adjacent side (the axis), but the shape that you get is a straight circular cone. 
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3 years ago
Rewrite the expression with rational exponents as a radical expression by extending the properties of integer exponents.
ra1l [238]

The expression will be written as \rm \sqrt[8]{2^5}., the correct option is A.

<h3>What are Exponents?</h3>

Exponents are the base raised to a power, It is written in the superscript of a number.

The expression given in the statement can be written as

\rm \dfrac{ 2^{7/8}}{2^{1/4}}

By the Exponent rule,

\rm \dfrac{a^m}{a^n} = a^{m-n}

So the expression can be written as

<h3>=\rm { 2^{7/8-1/4}</h3>

=\rm 2^{5/8}

=\rm \sqrt[8]{2^5}

Therefore, in radical form, the expression will be written as \rm \sqrt[8]{2^5}., the correct option is A.

The complete question is

Rewrite the rational exponent as a radical by extending the properties of integer exponents.

2 to the 7 over 8 power, all over 2 to the 1 over 4 power

the eighth root of 2 to the fifth power

the fifth root of 2 to the eighth power

the square root of 2 to the 5 over 8 power

the fourth root of 2 to the sixth power

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6 0
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