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GREYUIT [131]
8 months ago
11

A rectangular garden has a walkway around it. The area of the garden is 6(6.5x + 2.5). The combined area of the garden and the w

alkway is 6.5(8x + 6). Find the area of the walkway around the garden as the sum of two terms.
Mathematics
1 answer:
Rasek [7]8 months ago
7 0

According to the information given in the exercise, the following expression represents the area of the rectangular garden:

6\mleft(6.5x+2.5\mright)

And the following expression represents the combined area of the walkway around the rectangular garden and the area of the garden:

6.5\mleft(8x+6\mright)

You can identify that the word "combined" indicates that that expression was obtained by adding both areas.

Knowing the above, you can set up the following equation:

6(6.5x+2.5)+A=6.5(8x+6)

Where "A" is the area of the walkway around the rectangular garden.

Solving for "A", you get the following expression:

\begin{gathered} A=6.5(8x+6)-6(6.5x+2.5) \\ A=52x+39-39x-15 \\ A=13x+24 \end{gathered}

The answer is:

13x+24

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Read 2 more answers
The length of a rectangle is 1 inch less than twice the width. the area is 21 inches^2 what is the length?
ale4655 [162]
Hi.

Formula for area: A = 2l + 2w, where l is the length and w is the width.

Given information:
• l = 2w - 1
• A = 21 in^2

We can plug in our values accordingly and solve for w.

A = 2l + 2w
21 = 2(2w - 1) + 2w
21 = 4w - 2 + 2w
23 = 6w - 2
23 = 6w
3.83 = w

Plug 3.83 for w into 2w - 1 to find length.

2(3.83) - 1
7.66 - 1
6.66

Finally, check your work by plugging your values into the original equation.

21 = 2(6.66) + 2(3.83)
21 = 13.32 + 7.66
21 = 20.98

Answer:
The length is approximately 6.66 inches.
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3 years ago
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