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Dmitry_Shevchenko [17]
3 years ago
10

Help Me for number 2

Mathematics
1 answer:
Andreas93 [3]3 years ago
3 0
He forgot to multiply 8*2
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If the point A is located at (-5,-3) and A’ is the image of A after being rotated about the origin by 270 (counter clockwise). W
Rom4ik [11]

Answer:

D (-3, 5)

Step-by-step explanation:

270 counter clockwise is the same as 90 clockwise.

For a 90° clockwise or 270° counter clockwise, take the opposite of the x coordinate then switch the coordinates.

(-5, -3) -----> (5, -3) ------> (-3, 5)

You can also rotate your screen 90° clockwise to see the new coordinates for A.

3 0
3 years ago
Which term describes the red curve in the figure below?
Scorpion4ik [409]

Answer:

Hyperbola

Step-by-step explanation:

Its just like a parabola, but with 2 equal cones making them on opposite sides.

3 0
2 years ago
Read 2 more answers
Jeremy swims for 5 3/5 kilometers in a 7 Day period. she swims the same distance each day. what distance does he swim in each da
disa [49]

Answer:

Step-by-step explanation:

You turn 5 3/5 into an improper fraction, to do that you do 5 x 5 = 25 then 25 + 3 = 28/5

so in a 7 day period she swims 5.6 kilometers. So you have to do 5.6/7 = 0.8

So it would be 0.8 kilometers in a day which is 4/5 kilometers so I don't know if the answers were just wrong?

5 0
3 years ago
1.There are 3 High Schools and 14 Elementary Schools in the district. How can you write the ratio of High Schools to Elementary
adell [148]
1. 3 high schools: 14 elementary schools
6 0
3 years ago
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The diagram shows a sector of a circle radius 10cm
Yuki888 [10]

Answer:

\text{Perimeter of sector = 43.6 (Rounded to the nearest tenth.)}

Step-by-step explanation:

\text{Perimeter of the sector = Radius + arc length + radius}

\text{Radius = 10 cm}

\text{Perimeter of the sector = 10 + arc length + 10  }

 \text{Perimeter of the sector = 20 + arc length  }

\text{arc length   = (sector angle/ 360 ) * perimeter of the circle}

\text{Perimeter of a circle }=2\pi r

\text{sector angle} = 135

\text{arc length}   =  (135/ 360 ) * 2\pi (10)

= (3/8) 20\pi

= 15\pi /2

\text{Using  }\pi =3.14

= 15 * 3.14 /2

= 23.55

\text{Perimeter of the sector = 20  + 23.55}

= 43.55

= 43.6  cm

\text{perimeter of the sector  = 43.6  cm }

8 0
2 years ago
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