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2 years ago

Which list has three equivalent fractions for 2/5

Mathematics

2 answers:

Aleksandr [31]2 years ago

8 0

Answer:

The correct answer is B.

We have 4 / 10 = ( 2 x 2 ) / ( 2 x 5 );

6 / 15 = ( 3 x 2 ) / ( 3 x 5 );

8 / 20 = ( 4 x 2 ) / ( 4 x 5 );

Step-by-step explanation:

stich3 [128]2 years ago

8 0

Answer: Your correct answer would be B.

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2/5 of the students in the class received an invitation to Sari's party. (a) if there are 35 students in Sari's class, how many

astraxan [27]

a) (2/5) x 35 = 14 students received invitations

b) 35-14 = 21 students didn’t receive invitations

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3 years ago

Alison has $4 less than twice the amount Ben has. Which expression represents Alison’s amount if Ben has m dollars?

fredd [130]

Answer:

2m-4

Step-by-step explanation:

because she has double his amount (2*m) but $4 less therefore 2m-4

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3 years ago

Read 2 more answers

Complete this statement: 20 a x 2 + 25 a x + 15 a = 5 a 20 a x 2 + 25 a x + 15 a = 5 a

liubo4ka [24]

Answer:

Step-by-step explanation:

(((22•5ax2) + 25ax) + 15a) - 5 = 0

Step 2 :

Step 3 :

Pulling out like terms :

3.1 Pull out like factors :

20ax2 + 25ax + 15a - 5 =

5 • (4ax2 + 5ax + 3a - 1)

Equation at the end of step 3 :

5 • (4ax2 + 5ax + 3a - 1) = 0

Step 4 :

Equations which are never true :

4.1 Solve : 5 = 0

4 0

3 years ago

to troubleshoot a problem in a complex computer system you need to seek help from a ____ team. ( tech)

ioda

Here you need an adjective of the given word (Tech), so the answer is technical.

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2 years ago

Read 2 more answers

The height of a trapezoid is 6 in. and it’s area is 72 in to the 2nd power. One base of the trapezoid is 6 inches longer than th

Vitek1552 [10]

Given:

The height of the given trapezoid = 6 in

The area of the trapezoid = 72 in²

Also given, one base of the trapezoid is 6 inches longer than the other base

To find the lengths of the bases.

Formula

The area of the trapezoid is

$A=\frac{1}{2} (b_{1} +b_{2} )h$

where, h be the height of the trapezoid

$b_{1}$ be the shorter base

$b_{2}$ be the longer base

As per the given problem,

$b_{2}=b_{1} +6$

Now,

Putting, A=72, $b_{2}=b_{1}+6$ and h=6 we get,

$\frac{1}{2} (b_{1} +b_{1}+6)(6) = 72$

or, $b_{1}+b_{1}+6 = \frac{(72)(2)}{6}$

or, $2b_{1}+6 = 24$

or, $2b_{1}=24-6$

or, $b_{1}= \frac{18}{2}$

or, $b_{1}=9$

So,

The shorter base is 9 in and the other base is = (6+9) = 15 in

Hence,

One base is 9 inches for one of the bases and 15 inches for the other base.

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3 years ago