Answer:
What are you asking here? This is more like a statement.
Step-by-step explanation:
Slope intercept form is: y = mx + b
Isolate the y. First subtract 10x from both sides
10x (-10x) + 2y = 8 (-10x)
2y = -10x + 8
Isolate the y. Divide 2 from both sides and <em>all</em> terms.
(2y)/2 = (-10x + 8)/2
y = -5x + 4
y = -5x + 4 is your slope intercept form answer.
hope this helps
Answer:
See below.
Step-by-step explanation:
(112+2)+(92-4)
114+88
202
-hope it helps
Perpendicular lines refers to a pair of straight lines that intercept each other. The slopes of this lines are opposite reciprocal, meaning that it's multiplication is -1.
On this case they give you the equation of a line and a point, and is asked to find the equation of a line that is perpendicular to the given one, and that passes through this point.
-2x+3y=-6 Add 2x in both sides
3y=2x-6 Divide by 3 in both sides to isolate y
y=2/3x-6/3
The slope of the given line is 2/3, which means that the slope of a line perpendicular to this one, needs to be -3/2. Now you need to find the value of b or the y-intercept by substituting the given point into the formula y=mx+b, where letter m represents the slope.
y=mx+b Substitute the given point and the previous slope found
-2=(-3/2)(6)+b Combine like terms
-2=-9+b Add 9 in both sides to isolate b
7=b
The equation that represents the line perpendicular to -2x+3y=-6 and that passes through the point (6,-2), is y=-3/2x+7.
So if all same you just simplify The top : 2x+1+x+4 2x+x+1+4
3x+5 The bottom all same just use one .x-3 3x+5/x-3
