The system of equations to this graph is (1,1)
The length of the wire is the length of the hypotenuse of a triangle with one leg 60 inches and the other leg 8*4 in = 32 inches.
√(60² +32²) = √4624 = 68
The wire is 68 inches long.
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Consider what happens if you wrap a paper triangle of those dimensions around the pipe. The hypotenuse edge traces the path of the wire.
Answer: B, 35.41, 67.87, and 76.72
angle QRP=180-(64+47)
=69°
Using sin rule,
p/sinP=q/sinQ.
7.6/sin64=q/sin47
q=6.2cm
Using the formula;
area=1/2p*qsinR
we have;
1/2×7.6×6.2×sin69°=21.995
answer= 22