F(n) = 1st term - common difference (n - 1)
The operation is subtraction because the sequence is decreasing.
n = number of the term you are looking for
1st term = 1st number in the sequence, in this case, 16
common difference = difference between one number to the next
f(n) = 16 - 1(n-1)
Assuming we are looking for the 5th term.
f(5) = 16 - 1(5-1)
= 16 - 1(4)
= 16 - 4
= 12 * as you can see, 12 is the 5th term of the sequence.
If you are looking for the equivalent of the nth term, simply substitute n by the number you are looking for and solve the equation.
so, no breaks on the denominator thus, the LCD will be all three then.
![\bf \cfrac{3}{x-2}+\cfrac{4}{x-1}-\cfrac{1}{x}\implies \cfrac{[3x(x-1)]+[4x(x-2)]-[(x-2)(x-1)]}{x(x-2)(x-1)} \\\\\\ \cfrac{[3x^2-3x]+[4x^2-8x]-[x^2-3x+2]}{x(x-2)(x-1)} \\\\\\ \cfrac{3x^2-3x+4x^2-8x-x^2+3x-2}{x(x-2)(x-1)} \\\\\\ \cfrac{6x^2-8x-2}{x(x-2)(x-1)}\implies \cfrac{2(x^2-4x-1)}{x(x-2)(x-1)}](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7B3%7D%7Bx-2%7D%2B%5Ccfrac%7B4%7D%7Bx-1%7D-%5Ccfrac%7B1%7D%7Bx%7D%5Cimplies%20%5Ccfrac%7B%5B3x%28x-1%29%5D%2B%5B4x%28x-2%29%5D-%5B%28x-2%29%28x-1%29%5D%7D%7Bx%28x-2%29%28x-1%29%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Ccfrac%7B%5B3x%5E2-3x%5D%2B%5B4x%5E2-8x%5D-%5Bx%5E2-3x%2B2%5D%7D%7Bx%28x-2%29%28x-1%29%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Ccfrac%7B3x%5E2-3x%2B4x%5E2-8x-x%5E2%2B3x-2%7D%7Bx%28x-2%29%28x-1%29%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Ccfrac%7B6x%5E2-8x-2%7D%7Bx%28x-2%29%28x-1%29%7D%5Cimplies%20%5Ccfrac%7B2%28x%5E2-4x-1%29%7D%7Bx%28x-2%29%28x-1%29%7D)
Convert 1 kilogram to grams.
1 kilogram = 1000 grams
Therefore there are 1000 paper clips.
