To graph a line, first, we need to plot out values. Let’s find a few: if y is 2, -x would be 2-6, and x would be 4. If y is -2, x would be 8.
Now, all you have to do is put a few more of those points on a line graph and connect them.
Good luck!
This is the same as showing the following system of equations doesn't have a solution:

or in matrix form,

The quickest way to check if there is a solution is to check whether the coefficient matrix is invertible. If its determinant is 0, then it is not invertible.
And the quickest way to show that the determinant is 0 is by observing that the third row is a linear combination of the first two rows:
(-2, 9, 6) - (-3, 2, 1) = (-2 + 3, 9 - 2, 6 - 1) = (1, 7, 5)
So there are indeed no such scalars <em>c₁</em>, <em>c₂</em>, and <em>c₃</em>.
Answer: x = 9, 5
<u>Step-by-step explanation:</u>
4 | x - 7 | + 2 | x - 7 | = 12
6 | x - 7 | = 12 <em>added like terms</em>
| x - 7 | = 2 <em>divided both sides by 6</em>
x - 7 = 2 or x - 7 = -2 <em>removed absolute value sign</em>
x = 9 or x = 5 <em>added 7 to both sides of both equations</em>
Answer:
c
Step-by-step explanation:
look it up.................
Use calculating software for the quickest answer. The answer would be yes with a rate of increase of 1.75