Answer:
Step-by-step explanation:
- f(x) = 4x - 2
- f(x - 1) = 4(x - 1) - 2 = 4x - 4 - 2 = 4x - 6
Correct option is D
Answer:
b+6
Problem:
If the average of b and c is 8, and d=3b-4, what is the average of c and d in terms of b?
Step-by-step explanation:
We are given (b+c)/2=8 and d=3b-4.
We are asked to find (c+d)/2 in terms of variable, b.
We need to first solve (b+c)/2=8 for c.
Multiply both sides by 2: b+c=16.
Subtract b on both sides: c=16-b
Now let's plug in c=16-b and d=3b-4 into (c+d)/2:
([16-b]+[3b-4])/2
Combine like terms:
(12+2b)/2
Divide top and bottom by 2:
(6+1b)/1
Multiplicative identity property applied:
(6+b)/1
Anything divided by 1 is that anything:
(6+b)
6+b
b+6
5 by 3
3rd one
there we have to find hypotenuse.
Answer:
1000cm²=0.1m²
so 7000cm²=0.7m²
Step-by-step explanation:
please mark me as brainliest
Answer:
<u>With parentheses:</u>
(3 - 4)(4 + 5)/3
<u>Without parentheses:</u>
7 + 6 - 11 × 2
Hope this helps! :)
