The differnce of 2 perfect cubes
remember
a³-b³=(a-b)(a²+ab+b²)
so
Step-by-step explanation:
On each side of this quadrilateral, you have supplementary angles, in other wourds, angles that sum up to <em>one hundred eighty degrees</em>:
![\displaystyle 180° = [3y + 14]° + [10y - 29]° \\ 180° = [-15 + 13y]° \\ \frac{195}{13} = \frac{13y}{13} \\ \\ 15 = y; 59° = [3(15) + 14]° \\ \\ \\ \\ 180° = [5x - 2]° + [x + 14]° \\ 180° = [12 + 6x]° \\ \frac{168}{6} = \frac{6x}{6} \\ \\ 28 = x; 138° = [5(28) - 2]°](https://tex.z-dn.net/?f=%5Cdisplaystyle%20180%C2%B0%20%3D%20%5B3y%20%2B%2014%5D%C2%B0%20%2B%20%5B10y%20-%2029%5D%C2%B0%20%5C%5C%20180%C2%B0%20%3D%20%5B-15%20%2B%2013y%5D%C2%B0%20%5C%5C%20%5Cfrac%7B195%7D%7B13%7D%20%3D%20%5Cfrac%7B13y%7D%7B13%7D%20%5C%5C%20%5C%5C%2015%20%3D%20y%3B%2059%C2%B0%20%3D%20%5B3%2815%29%20%2B%2014%5D%C2%B0%20%5C%5C%20%5C%5C%20%5C%5C%20%5C%5C%20180%C2%B0%20%3D%20%5B5x%20-%202%5D%C2%B0%20%2B%20%5Bx%20%2B%2014%5D%C2%B0%20%5C%5C%20180%C2%B0%20%3D%20%5B12%20%2B%206x%5D%C2%B0%20%5C%5C%20%5Cfrac%7B168%7D%7B6%7D%20%3D%20%5Cfrac%7B6x%7D%7B6%7D%20%5C%5C%20%5C%5C%2028%20%3D%20x%3B%20138%C2%B0%20%3D%20%5B5%2828%29%20-%202%5D%C2%B0)
I am joyous to assist you at any time.
<span>{x=2+y
{-6x-6y=-12
-6(2+y) -6y = -12
-12 - 6y - 6y = -12
-12y = -12 + 12
-12y = 0
y = 0
x = 2 + y = 2 + 0 = 2
Answer: x=2, y=0</span>
Simple
scientific notation
8.009 × 10-3