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stiks02 [169]
3 years ago
7

Hey can you guys answer this pls

Mathematics
1 answer:
guajiro [1.7K]3 years ago
8 0

Answer:

2/9 + 7/9 = 1

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Keith had 694 green, yellow and blue marbles altogether. he had 3 times as many blue marbles as yellow marbles. there were 90 fe
scZoUnD [109]
Let the number of blue marbles be x

number of yellow marbles = x/3

number of green = x- 90

ATQ

x + x/3 + x - 90 = 694

2x + x/3 = 784

(6x + x)/3 = 784

7x/3 = 784

x = 784 x 3/7

x = 112 x 3

x = 336

number of blue marbles = 336
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3 years ago
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Talamunda to velcratia is 70 miles the train takes 5 hours to travel the distance at what unit rate is the train travilining
garri49 [273]
Your answer would be 14 because 70÷5= 14
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3 years ago
In quadrilateral ABDC, AB ∥ CD. Which additional piece of information is needed to determine that ABDC is a parallelogram?
N76 [4]
Since the definition of a parallelogram literally says that it's a quadrilateral with 2 parallel sides, we have AB || CD so the 2 other sides (AC and BD) need to be either similar or parallel (either works, due to that if they're similar we can prove that since AB || CD that they're parallel). B is our answer
3 0
3 years ago
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100 points for correct answer
Tems11 [23]

Answer:

\dfrac{x}{3}+\dfrac{3}{y}

Step-by-step explanation:

<u>Given fraction</u>:

\dfrac{xy+9}{3y}

\textsf{Apply the fraction rule} \quad \dfrac{a+b}{c}=\dfrac{a}{c}+\dfrac{b}{c}:

\implies \dfrac{xy}{3y}+\dfrac{9}{3y}

Rewrite 9 as 3 · 3:

\implies \dfrac{xy}{3y}+\dfrac{3 \cdot 3}{3y}

Cancel the common factor y in the first fraction and the common factor 3 in the second fraction:

\implies \dfrac{x\diagup\!\!\!\!y}{3\diagup\!\!\!\!y}+\dfrac{\diagup\!\!\!\!3 \cdot 3}{\diagup\!\!\!\!3y}

\implies \dfrac{x}{3}+\dfrac{3}{y}

7 0
1 year ago
Which are undefined?<br>sec(-pi/)<br>csc(3pi)<br>cot(7pi/2)<br>csc(-3pi/2)<br>cot(5pi/3)​
maxonik [38]

Step-by-step explanation:

after you draw a unit circle you will find the answer

cosec(3pi)=1/sin(3pi)

sin3pi=sinpi=0

so cosec3pi=1/0 which is undefined.

3 0
3 years ago
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