40min is 1/3
implies 20min is 1/6
60min is 1/3+1/6=3/6=1/2
Answer:
LCM = 92276
HCF = 1
Step-by-step explanation:
Answer:
X= 7 I'm sure
Step-by-step explanation:
If you want me to expand on the equation leave me a comment :)
Answer:
813.4 cm² (nearest tenth)
Step-by-step explanation:
<u>Volume of a cylinder</u>
![\sf V=\pi r^2 h \quad\textsf{(where r is the radius and h is the height)}](https://tex.z-dn.net/?f=%5Csf%20V%3D%5Cpi%20r%5E2%20h%20%5Cquad%5Ctextsf%7B%28where%20r%20is%20the%20radius%20and%20h%20is%20the%20height%29%7D)
Given:
Use the Volume of a Cylinder formula and the given values to find the <u>radius of the cylinder</u>:
![\implies \sf 1715=\pi r^2 (18)](https://tex.z-dn.net/?f=%5Cimplies%20%5Csf%201715%3D%5Cpi%20r%5E2%20%2818%29)
![\implies \sf r^2=\dfrac{1715}{18 \pi}](https://tex.z-dn.net/?f=%5Cimplies%20%5Csf%20r%5E2%3D%5Cdfrac%7B1715%7D%7B18%20%5Cpi%7D)
![\implies \sf r=\sqrt{\dfrac{1715}{18 \pi}](https://tex.z-dn.net/?f=%5Cimplies%20%5Csf%20r%3D%5Csqrt%7B%5Cdfrac%7B1715%7D%7B18%20%5Cpi%7D)
<u>Surface Area of a Cylinder</u>
![\sf SA=2 \pi r^2 + 2 \pi r h \quad\textsf{(where r is the radius and h is the height)}](https://tex.z-dn.net/?f=%5Csf%20SA%3D2%20%5Cpi%20r%5E2%20%2B%202%20%5Cpi%20r%20h%20%5Cquad%5Ctextsf%7B%28where%20r%20is%20the%20radius%20and%20h%20is%20the%20height%29%7D)
Substitute the given value of h and the found value of r into the formula and solve for SA:
![\implies \sf SA=2 \pi \left(\sqrt{\dfrac{1715}{18 \pi}\right)^2 + 2 \pi \left(\sqrt{\dfrac{1715}{18 \pi}\right)(18)](https://tex.z-dn.net/?f=%5Cimplies%20%5Csf%20SA%3D2%20%5Cpi%20%5Cleft%28%5Csqrt%7B%5Cdfrac%7B1715%7D%7B18%20%5Cpi%7D%5Cright%29%5E2%20%2B%202%20%5Cpi%20%5Cleft%28%5Csqrt%7B%5Cdfrac%7B1715%7D%7B18%20%5Cpi%7D%5Cright%29%2818%29)
![\implies \sf SA=2 \pi \left(\dfrac{1715}{18 \pi} \right) + 36 \pi \left(\sqrt{\dfrac{1715}{18 \pi}\right)](https://tex.z-dn.net/?f=%5Cimplies%20%5Csf%20SA%3D2%20%5Cpi%20%5Cleft%28%5Cdfrac%7B1715%7D%7B18%20%5Cpi%7D%20%5Cright%29%20%2B%2036%20%5Cpi%20%5Cleft%28%5Csqrt%7B%5Cdfrac%7B1715%7D%7B18%20%5Cpi%7D%5Cright%29)
![\implies \sf SA=\dfrac{1715}{9} + 36 \pi \left(\sqrt{\dfrac{1715}{18 \pi}\right)](https://tex.z-dn.net/?f=%5Cimplies%20%5Csf%20SA%3D%5Cdfrac%7B1715%7D%7B9%7D%20%2B%2036%20%5Cpi%20%5Cleft%28%5Csqrt%7B%5Cdfrac%7B1715%7D%7B18%20%5Cpi%7D%5Cright%29)
![\implies \sf SA=813.3908956...](https://tex.z-dn.net/?f=%5Cimplies%20%5Csf%20SA%3D813.3908956...)
Therefore, the surface area of the cylinder is 813.4 cm² (nearest tenth)
Answer:
It is given that a car traveling at 23 mi/h accelerates to 46 mi/h in 5 seconds.
This means that in 5 seconds it's speed continuously increases to reach 46 mi/h from 23 mi/h.
It maintains that speed for 5 seconds and then slows to a stop in 5 seconds.
This means that the speed of the car is constant i.e. 46 mi/h i.e. the graph is a straight horizontal line parallel to the time axis.
And then it decreases to reach 0 mi/h.