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ad-work [718]
3 years ago
11

Evaluate the expressions. -(1/3)^0 and (-9)^0​

Mathematics
1 answer:
mixas84 [53]3 years ago
7 0

Answer: 1

Step-by-step explanation:

To Evaluate the expression -(1/3)^0 and (-9)^0

It is important to note that any number raised to the power of 0 is 1, therefore,

-(1/3)^0 = -1

(-9)^0 = -1

(-1) x (-1) = +1

I hope this helps

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Uh please help 8x-4y=-4 <br> -3x+4y=5 <br> Subtract second equation from the first
crimeas [40]

Answer:

11x -8y = -9

Step-by-step explanation:

8x-4y=-4

-3x+4y=5

Subtract the second equation from the first

8x-4y=-4

-(-3x+4y=5)

-----------------------------

Distribute the minus sign

  8x-4y=-4

+(3x-4y=-5)

-----------------------------

11x -8y = -9

5 0
3 years ago
Will give the brains of me brains and my brains and maby ur brain to u how many brains can i give u if u ask this quetion right?
Mashcka [7]

Answer:

2.4 bags

Step-by-step explanation:

Uh you can keep your brains.

Using the data table, we get:

1, 2, 2, 3, 4 as our data.

Finding the mean:

(1+2+2+3+4)÷5=

12÷5=

2.4 bags

7 0
3 years ago
13. The least common multiple of two non-zero integers a and b is the unique positive integer m such that (i) m is a common mult
Vlad [161]

Answer:

[a,b] divides n

Step-by-step explanation:

Let us denote the least common multiple of a and b [a,b]=m.

We want to prove that m divides n, where n is a multiple of a and b.

We suppose m does not divide n, then by the Division Theorem, there exists q and r integers such that:

(1) ... n=mq+r, where 0<r<m

As n is a multiple of a and b, there exists s and t integers such that:

sa=n and tb=n

Same thing happens to m as it is the least common multiple, there exists u and v such that:

ua=m and vb=m

So (1) has the following form:

n=mq+r ⇒ sa=uaq+r ⇒sa-uaq=r⇒(s-uq)a=r and

n=mq+r ⇒ tb=vbq+r ⇒ tb-vbq=r⇒ (t-vq)b=r

So r is a multiple of a and b, but r<m which is a contradiction as, m is the least common multiple of a and b. So this concludes the proof.

So this means that \frac{ab}{m} is and integer.

As m= vb, then \frac{m}{b} is an integer, lets say \frac{m}{b}=v; and as m=ua, then \frac{m}{a}=u.

So \frac{ab}{m}v=\frac{ab}{m}\frac{m}{b}=a, so \frac{ab}{m} divides a; on the other hand, \frac{ab}{m}u=\frac{ab}{m}\frac{m}{a}=b, so \frac{ab}{m} divides b. From this we can conclude that \frac{ab}{m} is a common divisor of a and b.

4 0
3 years ago
Two ratios that are equvalent to 27:9
Alex787 [66]

Answer:

Step-by-step explanation:

hello :

hello :

1) divid by 3 :   27:9= 9/3

2) 9/3 = 3/1

4 0
3 years ago
Read 2 more answers
18) If the straight line y=m X touches the circle (x - 2)^2 + (y - 6)^2 = 4, then m= ......
fenix001 [56]

Answer:

(8) d. 4/3    (9) a. (X - 4)^2 + (y-4)^2= 25

Step-by-step explanation:

8. CENTER OF CIRCLE: O (2,6)

     radius of circle : r = √4 = 2

if m = 4/3 line: y = 4/3 x

perpendicular distance (d) from center of circle to line y = 4/3 x is

d = |((4/3 x 2) + (-1) x 6)| / √((4/3)² + (-1)²) = |(-10/3)| / √(25/9) = (10/3) / (5/3) = 2

d = r means line touch with circle

9. center of circle is the intersection of the diagonals of rectangle (4,4) and its radius is 5 (illustrated)

the equation of circle: (X - 4)^2 + (y-4)^2= 25

8 0
3 years ago
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