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2 years ago

Solve for the proportion 8/m+3 = 4/m

Mathematics

1 answer:

Ghella [55]2 years ago

7 0

Answer:

The Answer is m = - 4/3 Hope this helps :)

Step-by-step explanation:

If you want i can explain it with more detail

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A jar contains 30 red marbles 50 blue marbles and 20 white marbles what is the the theoretical probability of choosing a white m

svlad2 [7]

Theoretical probablity=desiredoutcomes/totalpossibleoutcomes

desired=number of white marbles=20
total possible=red+blue+white=30+50+20=100

so theoretical probablity=20/100=2/10=0.2=20%

7 0

3 years ago

Read 2 more answers

Let n be a whole number, and consider the statements below. p: n is a multiple of two. q: n is an even number. Which of the foll

Veseljchak [2.6K]

Answer:

C. p -> q

Step-by-step explanation:

Just did this on Edge2020. Hope this helps :)

5 0

3 years ago

Does going to a private university increase the chance that a student will graduate with student loan debt? A national poll by t

Snowcat [4.5K]

Answer:

Null hypothesis: $p \leq 0.69$

Alternative hypothesis: $p > 0.69$

Step-by-step explanation:

1) Data given and notation

n=1500 represent the random sample taken

X represent the number of graduates that had student loan debt in 2014

$\hat p=0.71$ estimated proportion of adults that said that it is morally wrong to not report all income on tax returns

$p_o=0.69$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that if there was a significant increase in the proportion of student loan debt for public and nonprofit colleges in 2014 respect to the value of 2013.:

Null hypothesis: $p \leq 0.69$

Alternative hypothesis: $p > 0.69$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.71 -0.69}{\sqrt{\frac{0.69(1-0.69)}{1500}}}=1.675$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level assumed is $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(Z>1.675)=0.047$

If we compare the p value obtained and using the significance level assumed $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of adults that said that it is morally wrong to not report all income on tax returns is not significantly higher than 0.69.