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svetoff [14.1K]
3 years ago
15

Find the ratio. Than find and interpret the value of the ratio

Mathematics
1 answer:
shepuryov [24]3 years ago
3 0

Answer:

The ratio is 3/4: 2

The value of the ratio is 3/8

The amount of club soda is 3/8 times the amount of white grape juice

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Answer:

y - 4 = -2/3 (x + 1)

Step-by-step explanation:

y2 - y1 / x2 - x1         -2 - 4 / 8 - (-1)      -6/9     = -2/3

y - 4 = -2/3 (x + 1)

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2 quarts in a cup<br> ddxxxxddddxvv
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Mrs. Lenz rented a scooter during her beach vacation. The cost of the scooter rental is shown for different periods of time. Wha
iragen [17]

Answer:

The unit rate of $10 per hour.

Step-by-step explanation:

Given

x = time

y = amount

(x,y) = (1,10)

See attachment for graph

Required

What does the given point represents

From the attachment, the origin of the graph is:

(x_1,y_1) = (0,0)

and we have the given point to be:

(x_2,y_2) = (1,10)

Calculate the slope (m)

m = \frac{y_2 - y_1}{x_2 - x_1}

m = \frac{10-0}{1-0}

m = \frac{10}{1}

m = 10

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Hence:

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8 0
2 years ago
Convert 0.2 m^ 3 , into c * m ^ 3​
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Step-by-step explanation:

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3 0
2 years ago
A projectile is fired with muzzle speed 220 m/s and an angle of elevation 45° from a position 30 m above ground level. Where doe
Allushta [10]

Answer:

  • 4968.6 m from where it was fired
  • 221.33 m/s

Step-by-step explanation:

For the purpose of this problem, we assume ballistic motion over a stationary flat Earth under the influence of gravity, with no air resistance.

We can divide the motion into two components, one vertical and one horizontal. For muzzle speed s and launch angle θ, the horizontal speed is presumed constant at s·cos(θ). The initial vertical speed is then s·sin(θ) and the (x, y) coordinates as a function of time are ...

  (x, y) = (s·cos(θ)·t, -4.9t² +s·sin(θ)·t + h₀) . . . . . where h₀ is the initial height

To find the range, we can solve the equation y=0 for t, and use this value of t to find x.

Using the quadratic formula, we find t at the time of landing to be ...

  t = (-s·sin(θ) - √((s·sin(θ))²-4(-4.9)(h₀)))/(2(-4.9))

  t = (s/9.8)(sin(θ) +√(sin(θ)² +19.6h₀/s²))

For s = 220, θ = 45°, and h₀ = 30, the time of flight is ...

  t ≈ 31.939 seconds

Then the horizontal travel is

  x = 220·cos(45°)·31.939 ≈ 4968.6 . . . . meters

__

As it happens, the value under the radical in the above expression for time, when multiplied by s, is the vertical speed at landing. The horizontal speed remains s·cos(θ), so the resultant speed is the Pythagorean sum of these:

  landing speed = s·√(cos(θ)² +sin(θ)² +19.6h₀/s²) ≈ s√(1 +0.012149)

  ≈ 221.33 m/s

_____

Note that the landing speed represents the speed the projectile has as a consequence of the potential energy of its initial height being converted to kinetic energy that adds to the kinetic energy due to its initial muzzle velocity.

6 0
3 years ago
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