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Sladkaya [172]
3 years ago
8

Problem in the attachment

Mathematics
1 answer:
TEA [102]3 years ago
8 0
You can solve this by multiplying each numerator by the answer choices and trying to divide them. I can't get the fraction maker to work at the moment, so I'll write the calculations on a separate attachment.

As you can see, the only choice that works to eliminate both fractions is the fourth choice, 50x.

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What is the value of x?
Dmitriy789 [7]
You have to start with the left triangle and find the side lengths. Since it is a 45-45-90, both sides are the same. Rule for this is hyp= sqrt2 * leg
Since hyp = 6sqrt2, the leg is 6.
The leg is also the hypotenuse of the triangle on the right side.
x is the side across from the hypotenuse and it is the short leg so x = (1/2)6
x = 3
3 0
4 years ago
What is 60% of 20?<br><br><br><br> PLEASE ANSWER ASAP
natulia [17]

Answer:

the answer would be 12

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Help asap will give 40 points
Vera_Pavlovna [14]

Answer: 1/3

Step-by-step explanation:

3 0
2 years ago
Let f ( x ) = 10 x + 14 f − 1 ( x ) =
Agata [3.3K]

Answer:

  f^-1(x) = (x -14)/10

Step-by-step explanation:

You can find the inverse function by solving for y:

  x = f(y)

Here, that is ...

  x = 10y +14 . . . . . use the definition of f(y)

  x -14 = 10y . . . . . . subtract 14

  (x -14)/10 = y . . . . divide by the coefficient of y

So, your inverse function is ...

  f^-1(x) = (x -14)/10

6 0
3 years ago
Use the given values of n and p to find the minimum usual value μ−2σ and the maximum usual value μ+2σ. Round to the nearest hund
lbvjy [14]

Answer:

μ−2σ = 1,089.26

μ+2σ = 1,097.62

Step-by-step explanation:

The standard deviation of a sample of size 'n' and proportion 'p' is:

\sigma=\sqrt{\frac{p*(1-p)}{n} }

If n=1139 and p =0.96, the standard deviation is:

\sigma=\sqrt{\frac{p*(1-p)}{n}}\\\sigma = 0.001836

The minimum and maximum usual values are:

\mu-2\sigma = (p-2\sigma)*n\\\mu+2\sigma = (p+2\sigma)*n

\mu-2\sigma = (0.96-2*0.001836)*1139\\\mu-2\sigma = 1,089.26\\\mu+2\sigma = (0.96+2*0.001836)*1139\\\mu+2\sigma = 1,097.62

5 0
3 years ago
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