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Ganezh [65]
3 years ago
7

How do you find the volume of a rectangular pyramid with a rectangular prism at the bottom

Mathematics
1 answer:
Mariulka [41]3 years ago
7 0
To find the volume of a rectangular pyramid, you need to know the length and width of the base and the height of the pyramid. Then, take those values, plug them into the formula for the volume of a rectangular pyramid, and simplify to get your answer! Watch this tutorial to see how it's done!
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Sarah would like to make a 6 lb nut mixture that is 60% peanuts and 40% almonds. She has several pounds of a mixture that is 80%
ivolga24 [154]

Answer:  

<em>a.  The system of equations that models the situation is....</em>

<em>     0.80x+0.50y=3.60\\\\ 0.20x+0.50y=2.40</em>

<em>b.  The solution to the system:  x = 2 and y = 4 </em>

<em>The amount of 80/20 mixture is 2 pounds and the amount of 50/50              mixture is 4 pounds.</em>

Step-by-step explanation:

Suppose, the amount of 80/20 mixture is  x pounds and the amount of 50/50 mixture is  y pounds.

So, the amount of peanuts in 80/20 mixture = 0.80x pound and the amount of almonds in 80/20 mixture =0.20x pound.

And the amount of peanuts in 50/50 mixture =0.50y pound and the amount of almonds in 50/50 mixture =0.50y pound.

Now, Sarah would like to make a 6 pounds nut mixture that is 60% peanuts and 40% almonds.

So, the amount of peanuts in that mixture =(6\times 0.60)=3.60 pounds

and the amount of almonds in that mixture =(6 \times 0.40)= 2.40 pounds.

So, the system of equations will be.........

0.80x+0.50y=3.60 ...................(1)\\\\ 0.20x+0.50y=2.40...................(2)

Subtracting equation (2) from equation (1), we will get.....

(0.80x+0.50y)-(0.20x+0.50y)=3.60-2.40\\ \\ 0.60x=1.20\\ \\ x= \frac{1.20}{0.60}=2

Now, plugging this x=2 into equation (1), we will get......

0.80(2)+0.50y=3.60\\ \\ 1.60+0.50y=3.60\\ \\ 0.50y=3.60-1.60=2\\ \\ y=\frac{2}{0.50}=4

So, the amount of 80/20 mixture is 2 pounds and the amount of 50/50 mixture is 4 pounds.

7 0
3 years ago
It is desired to compare the hourly rate of an entry-level job in two fast-food chains. Eight locations for each chain are rando
notka56 [123]

Answer:

It can be concluded that at 5% significance level that there is no difference in the amount paid by chain A and chain B for the job under consideration

Step by Step Solution:

The given data are;

Chain A 4.25, 4.75, 3.80, 4.50, 3.90, 5.00, 4.00, 3.80

Chain B 4.60, 4.65, 3.85, 4.00, 4.80, 4.00, 4.50, 3.65

Using the functions of Microsoft Excel, we get;

The mean hourly rate for fast-food Chain A, \overline x_1 = 4.25

The standard deviation hourly rate for fast-food Chain A, s₁ = 0.457478

The mean hourly rate for fast-food Chain B, \overline x_2 = 4.25625

The standard deviation hourly rate for fast-food Chain B, s₂ = 0.429649

The significance level, α = 5%

The null hypothesis, H₀:  \overline x_1 = \overline x_2

The alternative hypothesis, Hₐ:  \overline x_1 ≠ \overline x_2

The pooled variance, S_p^2, is given as follows;

S_p^2 = \dfrac{s_1^2 \cdot (n_1 - 1) + s_2^2\cdot (n_2-1)}{(n_1 - 1)+ (n_2 -1)}

Therefore, we have;

S_p^2 = \dfrac{0.457478^2 \cdot (8 - 1) + 0.429649^2\cdot (8-1)}{(8 - 1)+ (8 -1)} \approx 0.19682

The test statistic is given as follows;

t=\dfrac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{S_{p}^{2} \cdot \left(\dfrac{1 }{n_{1}}+\dfrac{1}{n_{2}}\right)}}

Therefore, we have;

t=\dfrac{(4.25-4.25625)}{\sqrt{0.19682 \times \left(\dfrac{1 }{8}+\dfrac{1}{8}\right)}} \approx -0.028176

The degrees of freedom, df = n₁ + n₂ - 2 = 8 + 8 - 2 = 14

At 5% significance level, the critical t = 2.145

Therefore, given that the absolute value of the test statistic is less than the critical 't', we fail to reject the null hypothesis and it can be concluded that at 5% significance level that chain A pays the same as chain B for the job under consideration

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=3%28%20%7Bx%7D%5E%7B2%7D%20%20%2B%7B3x%7D%5E%7B2%7D%20%20-%202%29" id="TexFormula1" title="3(
Juliette [100K]
The answer should be 12x^2-6
7 0
3 years ago
Read 2 more answers
A. The slope of the curve y=x^3- 1 at the point P(1,0) is<br> .
Ierofanga [76]

Answer:

3

Step-by-step explanation:

The measure of the slope is \frac{dy}{dx} at x = a

Differentiate using the power rule

\frac{d}{dx}(ax^{n}) = nax^{n-1}

Given

y = x³ - 1, then

\frac{dy}{dx} = 3x²

The slope at (1, 0) is

\frac{dy}{dx} = 3(1)² = 3

5 0
3 years ago
Need help 8th grade math
Scorpion4ik [409]

Answer:

second

Step-by-step explanation:

5 0
3 years ago
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