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Lady_Fox [76]
3 years ago
7

A box contains 5 red chips, 3 blue chips, and 7 white chips. A chip is randomly selected, replaced, and a second chip is selecte

d. Find the probability of selecting a blue chip, then a white chip.
Mathematics
1 answer:
Basile [38]3 years ago
5 0
So add the number of chips together
5+3+7=15
So the chance of a red chip is 5/15
Blue 3/15
White 7/15
So the blue chips would be 3/15 chance
So take away one chip 14
So 7/14
The awnsers is
The probability of selecting a blue chip will be 3/15 and for a white chip it is 7/14
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Who sets the price in a monopolistic competition?
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Step-by-step explanation:

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Need help on the last ones
OlgaM077 [116]

the diagonals of a rhombus bisect the angles.

if angle 2 is 48, angle 4 is also 48. therefore, by alternating interior angles, angles 9 and 7 are also 48. This means m<MOH = 96.

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I'm not sure I understand the context of 5. how are do they expect you to solve for x? you could solve for it in terms of m<3, which would mean x = (m<3 + 6)/8.

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