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Lera25 [3.4K]
2 years ago
15

A track has lanes 1 meter wide. The turn radius of the inner lane is 25 meters. To make a fair race, the starting line in each l

ane must be staggered so each competitor runs the same distance to the finish line. find the distance between the starting line in one lane to the starting lane in the next lane. Is the same distance used between first and second lanes and between second and third lanes?
Mathematics
1 answer:
Angelina_Jolie [31]2 years ago
8 0
Assuming that there are N lanes and runners are running in the middle of each lane, 
width of each lane = (1/N) [m]turning of first lane = π×(R+(1/N)×(1/2))
turning of second lane = π×(R+((1/N)×(1/2))+(1/N))

you can get the difference in turning lane simply by subtracting turning of first lane from turning of second lane.  
If i worked the problem correctly, it should be π×(1/N) meter difference between each lane
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Which systems of equations intersect at point A in this graph?
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Answer:

The point of intersection of the system of equations is:

(x, y) =  (-2, 1)

The correct system of equations intersect at point A in this graph will be:

\begin{bmatrix}y=4x+9\\ y=-3x-5\end{bmatrix}

Thus, the second option is correct.

Step-by-step explanation:

Given the point

  • A (-2, 1)

Let us check the system of equations to determine whether it intersect at point A in this graph.

Given the system of equations

\begin{bmatrix}y=4x+9\\ y=-3x-5\end{bmatrix}

Arrange equation variable for elimination

\begin{bmatrix}y-4x=9\\ y+3x=-5\end{bmatrix}

so

y+3x=-5

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\underline{y-4x=9}

7x=-14

so the system of equations becomes

\begin{bmatrix}y-4x=9\\ 7x=-14\end{bmatrix}

Solve 7x = -14 for x

7x=-14

Divide both sides by 7

\frac{7x}{7}=\frac{-14}{7}

Simplify

x = -2

For y - 4x = 9 plug in x = 2

y-4\left(-2\right)=9

y+4\cdot \:2=9

y+8=9

Subtract 8 from both sides

y+8-8=9-8

Simplify

y = 1

Thus, the solution to the system of equations is:

(x, y) = (-2, 1)

From the attached graph, it is also clear that the system of equations intersects at point x = -2, and y = 1.

In other words, the point of intersection of the system of equations is:

(x, y) =  (-2, 1)

Therefore, the correct system of equations intersect at point A in this graph will be:

\begin{bmatrix}y=4x+9\\ y=-3x-5\end{bmatrix}

Thus, the second option is correct.

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