Give an example of a line that is parallel to y=3x-4

What is the order of the surd 5?

Reptile [31]

Answer:

5

Step-by-step explanation:

the order of the surd is 5

5 0

2 years ago

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Please help me with this !! I REALLY need to have good grades because...Back story I had my phone and I broke it and I can't get

nevsk [136]

Answer:

Transformation include reflecting and dilating of points

The scale factor from PQR to P'Q'R' is 1/4

The coordinates of P"Q"R" are P"=(-1,0) Q"=(0,-1) R"=(2,-1) .

PQR and P′'Q′'R′' are not congruent

The points are given as:

p=(4,0)

q=(0,-4)

r=(-8,-4)

p'=(1,0)

q'=(0-1)

r'=(-2,-1)

(a)The scale factor from PQR to P'Q'R

To do this, we make use of corresponding sides QR and Q'R

So, the scale factor (k) is:

k=q'r'/qr

k=2/8

k=1/4

(b) The coordinates of P"Q"R from reflecting P'Q'R' about the y-axis

The rule of this transformation is:

(x,y)--------(-x,y)

So, we have:

p"=(-1,0)

q"=(0,-1)

r"=(2,-1)

(c) Are triangle PQR and P"Q'R" congruent?

No they are not

This is so because

PQR was dilated by 1/4 to get P'Q'R

P'Q'R' and P"Q"R" are congruent

Hence, PQR and P′'Q′'R′' are not congruent

Step-by-step explanation:

4 0

2 years ago

Should be fairly easy..

Harlamova29_29 [7]

Answer:

<u>72 cm²</u>

Step-by-step explanation:

Area of a ∆ = 1/2 × b × h

b = 12 cm

h = 12 cm

Area = 1/2 × 12 × 12

= 1/2 × 144

= <u>72 cm²</u>

4 0

2 years ago

Use the theorem in Sec. 28 to show that if f (z) is analytic and not constant throughout a domain D, then it cannot be constant

alexandr1967 [171]

Answer:

The value of f(z) is not constant in any neighbourhood of D. The proof is as explained in the explaination.

Step-by-step explanation:

Given

For any given function f(z), it is analytic and not constant throughout a domain D

To Prove

The function f(z) is non-constant constant in the neighbourhood lying in D.

Proof

1-Assume that the value of f(z) is analytic and has a constant throughout some neighbourhood in D which is ω₀

2-Now consider another function F₁(z) where

F₁(z)=f(z)-ω₀

3-As f(z) is analytic throughout D and F₁(z) is a difference of an analytic function and a constant so it is also an analytic function.

4-Assume that the value of F₁(z) is 0 throughout the domain D thus F₁(z)≡0 in domain D.

5-Replacing value of F₁(z) in the above gives:

F₁(z)≡0 in domain D

f(z)-ω₀≡0 in domain D

f(z)≡0+ω₀ in domain D

f(z)≡ω₀ in domain D

So this indicates that the value of f(z) for all values in domain D is a constant ω₀.

This contradicts with the initial given statement, where the value of f(z) is not constant thus the assumption is wrong and the value of f(z) is not constant in any neighbourhood of D.

6 0

2 years ago

In which choice do all the points lie on the same line

Ronch [10]

Answer:

(0,0) (1,2) (2,4) (3,6)

Step-by-step explanation:

They all share the same slope which is 1/2

4 0

2 years ago

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