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krok68 [10]
3 years ago
10

What is 20% of 30% of 40% of $50

Mathematics
1 answer:
GarryVolchara [31]3 years ago
6 0

20% of $50 = $10

30% of $50 = $15

40% of $50 = $20

Multiply 20% by $50

30% by $50

40% by %50

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Luisa recieved $108 for a necklace she sold on an online auction. The auction site took a fe of 10% of selling price. What was t
Vera_Pavlovna [14]
I believe it might be 107.9 after if that’s what your asking-like taking off 10% of $108.
3 0
3 years ago
How can I simplify/rewrite the 1st(top) equation into the 2nd(Botton),please show a step by step solution.​
Vaselesa [24]

Answer:

see below

Step-by-step explanation:

-2(4 - \frac{x}{2} )^{5} + C

Think of the above as:

  -\frac{2}{1} * (\frac{8}{2} - \frac{x}{2} )^{5} + C

= -\frac{2}{1} * \frac{(8 - x)^{5}}{2^{5}}  + C

= -\frac{2}{1} * \frac{(8 - x)^{5}}{32}  + C

= -\frac{1}{1} * \frac{(8 - x)^{5}}{16}  + C

=   \frac{-1(8 - x)^{5}}{16}  + C

=   \frac{(-8 + x)^{5}}{16}  + C

Can flip it around to be...

\frac{(x - 8)^{5}}{16}  + C

4 0
3 years ago
What three digits are in the units period 4,083,817
lorasvet [3.4K]
8,1,7 I hope this helps
5 0
3 years ago
Read 2 more answers
X² – 3x-7<br> x+2<br> Divide the following using synthetic division
Ksenya-84 [330]

Answer:

x-5+ \frac{3}{x+2}

Step-by-step explanation:

If x+2 is a factor, -2 is a zero. So we can put -2 in the left-hand corner of your synthetic division, bring the coefficients down so you'll have a set up like this:

-2 |   1    -3    -7

____________

1. bring down the 1:

-2 |   1    -3    -7

____________

       1

2. multiply that by -2 and enter the result underneath 3:

-2 |   1    -3    -7

             -2

___________

       1

a. then, add through:

-2 |   1    -3    -7

             -2

___________

       1     -5

3. Do the same for -5 (multiply by the zero -2), enter that underneath -7 and add through:

-2 |   1    -3    -7

             -2    10

___________

       1     -5    3

Now, reassign the coefficients to their x. Because we already factored out an x with the zero, the 1 is assigned to 'x' rather than back to 'x^{2}'. The '-5' will not have an x attached. '3' is your remainder and cannot be divided out any further, so it will be written as \frac{3}{x+2}. Finally, just put them back together to get x-5+\frac{3}{x+2}.

Hope this helped!

4 0
3 years ago
The equation with the restriction x, is on the terminal side of an angle in standard position.
marishachu [46]
4 because it hits the dextran quadran of the terminal side in a standered position while  also...

just imagin a triange with four on top and -2 on side

5 0
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