Area= 12m * 12m = 144m^2 *7.00$ = 1008$.
Final answer: 1008$
Answer:
<u>15</u>
<u>2x</u>
Step-by-step explanation:
Mid term :
Q1 = (88 + 85)/2 = 86.5
Q2 = (92 + 95)/2 = 93.5
Q3 = 100
IQR = Q3 - Q1 = 100 - 86.5 = 13.5
final exams :
Q1 = (65 + 78)/2 = 71.5
Q2 = (88 + 82)/2 = 85
Q3 = (95 + 93)/2 = 94
IQR = Q3 - Q1 = 94 - 71.5 = 22.5
so the final exams has the largest IQR
Answer:
the answer is B.
Step-by-step explanation:
It makes the problem solve smoother.
Answer:
a
The average cost is 
b
The standard deviation of cost is
Step-by-step explanation:
From the question we are told that




The cost of replacing the two component is C = 50 + 2 X + 4 Y
The variance of X is mathematically represented as
V(X) =
Substituting values
![V[X] = 24 - 4^2](https://tex.z-dn.net/?f=V%5BX%5D%20%3D%20%2024%20-%204%5E2)
![V[X] =8](https://tex.z-dn.net/?f=V%5BX%5D%20%3D8)
The variance of Y is mathematically represented as
V(Y) =
Substituting values
![V[Y] = 8 - 2^2](https://tex.z-dn.net/?f=V%5BY%5D%20%3D%20%208%20-%202%5E2)
![V[X] =4](https://tex.z-dn.net/?f=V%5BX%5D%20%3D4)
The average of replacing the two component is

substituting value


The variance of replacing the two component is
Note: The variance of constant is zero
and X and Y are independent
=> 
substituting values
=>
=>
=> 
The standard deviation is
substituting values