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Nezavi [6.7K]
3 years ago
13

$149 MP3 player 40% discount

Mathematics
1 answer:
MatroZZZ [7]3 years ago
5 0

40% of 149 is 59.60

149-59.60= 89.40

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Find x for the problem
oee [108]

Answer:

14.4

Step-by-step explanation:

sin x = 24/30

x = sin^-1 (24/30) = 53.13

sin 53.13 = x/18

x = sin 53.13 x 18 = 14.4

6 0
2 years ago
Which expression are equivalent to -3-(7.5+4)
Hunter-Best [27]
-14.5

Basically, -(7.5+4) is -11.5 and then combine -3 with -11.5 which yields -14.5
3 0
3 years ago
The bakery shop purchased 7 2/10 pounds of sugar and 7 5/10 pounds of flour. How much sugar and flour did they purchase in all?​
gizmo_the_mogwai [7]

Answer:

Sugar = 1-2/5 pounds, Flour = 3-1/2 pounds

Together = 5-9/10 pounds

Step-by-step explanation:

sugar = 7(2/10)

flour = 7(5/10)

sugar + flour = 7(2/10) + 7(5/10)

sugar = 14/10 or 1-2/5 pounds

flour = 35/10 or 3-1/2 pounds

5 0
3 years ago
three bags of sweets weigh 27/4 kg. two of them have the same weight and the third bag is heavier than each of the bags of equal
Nana76 [90]

I'm here buddy,

so, let's take the value of the two bags with equal weight as x.

=     x + x + (x + \frac{6}{5}) = \frac{27}{4}

=     3x + \frac{6}{5} = \frac{27}{4}

=     3x = \frac{27}{4} - \frac{6}{5}

( let's take the LCM of 4 and 5 = 20

=     3x = \frac{135}{20} - \frac{24}{20}

=     3x = \frac{111}{20}

=       x = \frac{111}{20} ÷ \frac{3}{1} = \frac{111}{20} × \frac{1}{3} = \frac{37}{20}

So, the weight of the equal bags are \frac{37}{20} and the weight of the third bag ( heavy one ) is \frac{37}{20} + \frac{6}{5} = \frac{37}{20} + \frac{24}{20} = \frac{61}{20}

1st bag =     \frac{37}{20} kg

2nd bag =  \frac{37}{20} kg

3rd bag =   \frac{61}{20} kg

Hope it helps...

7 0
3 years ago
Lol I have 21 warnings so if you wanna friend me friend girlllama0792
ycow [4]

Answer:

yeah i did kenn

Step-by-step explanation:

hi

1

4 0
3 years ago
Read 2 more answers
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