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HACTEHA [7]
3 years ago
9

Use the picture for the question and the answer choices:)

Mathematics
1 answer:
Orlov [11]3 years ago
8 0

Parenthesis first 5-2=3.

7^2=49

-3*3=-9

49-9=40.

A is your answer.


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Which physical feature is shown?
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Answer:

APPALACHIAN MOUNTAINS

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32, i believe is the answer

5 0
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Isaiah is having his house painted. He paid $525 for the required materials, and he will pay $30 an hour for the painters to com
alukav5142 [94]

Answer:

Step-by-step explanation:

x is the amount of hours it will take. Since he pays $30 per hour, your answer would be 30x + 525

7 0
3 years ago
Which number can each term of the equation be multiplied by to eliminate the fractions before solving?
scoray [572]

Answer: 12

Step-by-step explanation:

You can multiply by 12 because to get rid of the fractions all terms should be divided by the LCM (ie the smallest multiple that is exactly divisible by 2, 4 and 3)

Multiples of 3 = 3, 6, 9, 12

Multiples of 4 = 4, 8, 12, 16

Multiples of 2 = 2, 4, 6, 8, 10, 12

Therefore the fractions should be multiplied by 12

5 0
2 years ago
Read 2 more answers
A telemarketer is successful at getting people to donate money for her organization in 55% of all calls she makes. She must get
Tems11 [23]
An interesting twist to a binomial distribution problem.

Given:
p=55%=0.55 for probability of success in solicitation
x=4=number of successful solicitations
n=number of calls to be made
P(x,n,p)>=89.9%=0.899  (from context, it is >= and not =, which is almost impossible)

From context of question, all calls are assumed independent, with constant probability of success, so binomial distribution is applicable.

The number of successes, x, is then given by
P(x)=C(n,x)p^x(1-p)^{n-x}where
p=probability of success
n=number of trials
x=number of successesC(n,x)=\frac{n!}{x!(n-x)!}

Here we need n such that
P(x,n,p)>=0.899
given
x>=4, p=0.55, which means we need to find

Method 1: if a cumulative binomial distribution table is available, we can look up n=9,10,11 and find
P(x>=4,9,0.55)=0.834
P(x>=4,10,0.55)=0.898
P(x>=4,11,0.55)=0.939
So she must make (at least) 11 calls to make sure the probability of meeting her quota is 89.9% or more.

Method 2: using technology.
Similar to method 1, we can look up the probabilities directly, for n=9,10,11
P(x>=4,9,0.55)=0.834178
P(x>=4,10,0.55)=0.8980051
P(x>=4,11,0.55)=0.9390368

Method 3: using simple calculator
Here we need to calculate the probabilities for each value of n=10,11 and sum the probabilities of FAILURE S=P(0,n,0.55)+P(1,n,0.55)+P(2,n,0.55)+P(3,n,0.55)
so that the probability of success is 1-S.
For n=10,
P(0,10,0.55)=0.000341
P(1,10,0.55)=0.004162
P(2,10,0.55)=0.022890
P(3,10,0.55)=0.074603
So that
S=0.000341+0.004162+0.022890+0.074603
=0.101995
and Probability of getting 4 successes (or more) 
=1-S
=0.898005, missing target by 0.1%

So she will have to make 11 phone calls, bring up the probability to 93.9%.  The work is similar to that of n=10.
8 0
3 years ago
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