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NNADVOKAT [17]
3 years ago
14

A lake near the Arctic Circle is covered by a 2-meter-thick sheet of ice during the cold winter months. When spring arrives, the

warm air gradually melts the ice, causing its thickness to decrease at a constant rate. After 3 weeks, the sheet is only 1.25 meters thick.
Let y represent the ice sheet's thickness (in meters) after x weeks.
Mathematics
1 answer:
Kaylis [27]3 years ago
7 0

Answer:

The answer would be y-intercept and a point that is NOT an intercept

Step-by-step explanation:

To describe a point on the graph, we need a corresponding  

(x,y)(x,y)

(x,y)

left parenthesis, x, comma, y, right parenthesis

pair.

In our case, these are corresponding values of weeks since spring arrives and thickness of ice.

weeks since spring arrivedthickness of ice↓↓(x,y)\begin{aligned} \scriptsize\text{weeks since spring arrived}&\quad\scriptsize\text{thickness of ice} \\ \downarrow&\quad\downarrow \\ \large (x &,\quad\large y) \end{aligned}

weeks since spring arrived

↓

(x

​

thickness of ice

↓

,y)

​

To describe the slope of the graph, we need information about the rate of change of the relationship.

In our case, this is the rate at which the thickness of ice changes over time (in meters per week).

Hint #2

2 / 4

The ice is  

22

2

2

meters thick at the start of spring, when  

00

0

0

weeks have passed. This corresponds to the point  

(0,2)(0,2)

(0,2)

left parenthesis, 0, comma, 2, right parenthesis

and is a  

yy

y

y

-intercept.

Hint #3

3 / 4

After  

33

3

3

weeks, the sheet is only  

1.251.25

1.25

1, point, 25

meters thick. This corresponds to the point  

(3,1.25)(3,1.25)

(3,1.25)

left parenthesis, 3, comma, 1, point, 25, right parenthesis

and is not an intercept.

Hint #4

4 / 4

The  

yy

y

y

-intercept and a point that is not an intercept is given

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Please help :)))) ( attachment )
Anastaziya [24]
Let,
f(x) = -2x+34
g(x) = (-x/3) - 10
h(x) = -|3x|
k(x) = (x-2)^2

This is a trial and error type of problem (aka "guess and check"). There are 24 combinations to try out for each problem, so it might take a while. It turns out that 

g(h(k(f(15)))) = -6
f(k(g(h(8)))) = 2

So the order for part A should be: f, k, h, g
The order for part B should be: h, g, k f
note how I'm working from the right and moving left (working inside and moving out).


Here's proof of both claims

-----------------------------------------

Proof of Claim 1:

f(x) = -2x+34
f(15) = -2(15)+34
f(15) = 4
-----------------
k(x) = (x-2)^2
k(f(15)) = (f(15)-2)^2
k(f(15)) = (4-2)^2
k(f(15)) = 4
-----------------
h(x) = -|3x|
h(k(f(15))) = -|3*k(f(15))|
h(k(f(15))) = -|3*4|
h(k(f(15))) = -12
-----------------
g(x) = (-x/3) - 10
g(h(k(f(15))) ) = (-h(k(f(15))) /3) - 10
g(h(k(f(15))) ) = (-(-12) /3) - 10
g(h(k(f(15))) ) = -6

-----------------------------------------

Proof of Claim 2:

h(x) = -|3x|
h(8) = -|3*8|
h(8) = -24
---------------
g(x) = (-x/3) - 10
g(h(8)) = (-h(8)/3) - 10
g(h(8)) = (-(-24)/3) - 10
g(h(8)) = -2
---------------
k(x) = (x-2)^2
k(g(h(8))) = (g(h(8))-2)^2
k(g(h(8))) = (-2-2)^2
k(g(h(8))) = 16
---------------
f(x) = -2x+34
f(k(g(h(8))) ) = -2*(k(g(h(8))) )+34
f(k(g(h(8))) ) = -2*(16)+34
f(k(g(h(8))) ) = 2
5 0
4 years ago
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