9514 1404 393
Answer:
(i) x° = 70°, y° = 20°
(ii) ∠BAC ≈ 50.2°
(iii) 120
(iv) 300
Step-by-step explanation:
(i) Angle x° is congruent with the one marked 70°, as they are "alternate interior angles" with respect to the parallel north-south lines and transversal AB.
x = 70
The angle marked y° is the supplement to the one marked 160°.
y = 20
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(ii) The triangle interior angle at B is x° +y° = 70° +20° = 90°, so triangle ABC is a right triangle. With respect to angle BAC, side BA is adjacent, and side BC is opposite. Then ...
tan(∠BAC) = BC/BA = 120/100 = 1.2
∠BAC = arctan(1.2) ≈ 50.2°
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(iii) The bearing of C from A is the sum of the bearing of B from A and angle BAC.
bearing of C = 70° +50.2° = 120.2°
The three-digit bearing of C from A is 120.
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(iv) The bearing of A from C is 180 added to the bearing of C from A:
120 +180 = 300
The three-digit bearing of A from C is 300.
11t=120(12)
11t=1440
t=1440/11
However t is in hours and we want to know days so:
d=(1440/11)/24
d=1440/264
d=60/11
d=5 5/11 days<span>is a mixed number 5+5/11 days. Approximately 5.45 days....</span>
-72\sqrt(5) this is the answer i did all my math and i got this answer
Answer:
The common ratio is 0.10
Step-by-step explanation:
0.1 x 0.1 = 0.01
0.01 x 0.1 = 0.001
common ratio is the ratio of a term to the previous term.
0.1 is the previous term of 0.01
common ratio = 0.01/0.1 = 0.10
common ratio = 0.001/0.01 = 0.10