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Brilliant_brown [7]
3 years ago
13

Which statement about sutter’s work are true?

Mathematics
2 answers:
ale4655 [162]3 years ago
7 0

Answer:

The one that was listed. Unlike the ones on this question.

Step-by-step explanation:

Have

a

good

day

:)

Gnoma [55]3 years ago
3 0

Answer:

good question

Step-by-step explanation:

go to google i guess

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Determine the equation of the line that has an x intercept of 5 and y intercept of 7
garik1379 [7]

Answer:

y = −1.4x + 7

Step-by-step explanation:

There are 3 steps to find the Equation of the Straight Line

1. Find the slope of the line

2. Put the slope and one point into the "Point-Slope Formula"

3. Simplify

3 0
2 years ago
Answer ASAP and only if you know its correct<br><br> Brainliest to the correct answer!
rewona [7]

Hi!

Your answer is the 1st one, <u>36 inches of ribbon.</u>

The question states this is a square picture frame. That means that all the side lengths are the same.

We are given a side length of 6 inches.

In order to find the area of a square, we multiply the length and the width together, but since they are the same value, we are just doing 6 x 6.

6*6=36

5 0
2 years ago
Read 2 more answers
How do I solve this out??
GuDViN [60]
<h3>Answer:</h3>

(x, y) = (7, -5)

<h3>Step-by-step explanation:</h3>

It generally works well to follow directions.

The matrix of coefficients is ...

\left[\begin{array}{cc}2&4\\-5&3\end{array}\right]

Its inverse is the transpose of the cofactor matrix, divided by the determinant. That is ...

\dfrac{1}{26}\left[\begin{array}{ccc}3&-4\\5&2\end{array}\right]

So the solution is the product of this and the vector of constants [-6, -50]. That product is ...

... x = (3·(-6) +(-4)(-50))/26 = 7

... y = (5·(-6) +2·(-50))/26 = -5

The solution using inverse matrices is ...

... (x, y) = (7, -5)

7 0
3 years ago
What are the coordinates of the endpoints of the midsegment for DEF that is parallel to DE
Nutka1998 [239]

Answer:

\left(\dfrac{x_D+x_F}{2},\dfrac{y_D+y_F}{2}\right),  \left(\dfrac{x_E+x_F}{2},\dfrac{y_E+y_F}{2}\right).

Step-by-step explanation:

Let points D, E and F have coordinates (x_D,y_D),\ (x_E,y_E) and (x_F,y_F).

1. Midpoint M of segment DF has coordinates

\left(\dfrac{x_D+x_F}{2},\dfrac{y_D+y_F}{2}\right).

2. Midpoint N of segment EF has coordinates

\left(\dfrac{x_E+x_F}{2},\dfrac{y_E+y_F}{2}\right).

3. By the triangle midline theorem, midline MN is parallel to the side DE of the triangle DEF, then points M and N are endpoints of the midsegment for DEF that is parallel to DE.

6 0
3 years ago
Simplify the expression by combining like terms:<br><br> 4n+4(2n+3)
Anna007 [38]
First, you do the distributive property on:

4(2n+3)

You would get

8n+12

Then add the original part of the equation in (4n)

4n+8n+12

Combine like terms

12n+12 is the answer
7 0
3 years ago
Read 2 more answers
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