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stepan [7]
2 years ago
14

Evaluate the limit 9n^3 + 5n - 2/2n^3

Mathematics
1 answer:
VikaD [51]2 years ago
4 0

Answer:

9/2    if  n goes to infinity  and that the 2n^3 is under the whole expression

Step-by-step explanation:

Let me clear this .

find  limit  (9n^3  + 5*n  - 2)/ (2n^3)

as n --> infinity

Did I put the parentheses in the right spot?

because if you leave it the way you did, then the whole expression goes to positive infinity as n goes to infinity  But I will do this with parentheses

so

find  limit  (9n^3  + 5*n  - 2)/ (2n^3)

simplify expression

limit   (9/2)  +   5/(2n^2)   -   1/(n^3)

=  (9/2)  + 0  - 0

=  (9/2)

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A+b=77,a-b=13 care sun nr
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It's a simultaneous equation:
Steps:
1.Number the equations..

a+b=77 -1
a-b=13 -2

2. Choose what variable you want to use. In this case I would use the "b". Since the signs in front of the "b's" are different, add the two equations together

a + b = 77
+ + +
a (-b) = 13

Which gives;
2a = 90

Then solve to find a:
2a=90
a= 90/2
a=45

3.Then plug the "a" value into any of the original equations to find the "b" value. I would use equation 1 since the all the variables are positive.

a + b = 77
(45) + b = 77
b=77-45
b=32

4.Solution

a=45
b=32
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3 years ago
Helia invested 4000 AED for 3 years with a compound interest rate of 1.5%, Calculate the worth of her investment at the end of t
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Answer:

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Step-by-step explanation:

Given data

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A= 4000(1.015)^3

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Step-by-step explanation: apex

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Answer:

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Step-by-step explanation:

Given

P = \$24000

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Required

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