A. 2, 200, 2000
This is multiplying the number by 10 each time. In other words, just adding an extra zero to the end of it.
b. 340, 0.034
This one is moving the decimal place forward two places. 10^-2, so removing two zeros from the end of it until eventually you reach decimals and have to move the decimal forward twice, which is essentially what you're doing here.
c. 85700, 857, 0.857
In this one, you remove one zero from the end. You move the decimal forward once when you reach the decimals. This would be 10^-1
d. 444000, 4440000, 44400000
In this one, you multiply each one by 10. Add on a zero to each one.
e. 0.095, 9500000, 950000000
You multiply this one by 10^2, so the number increases.
Answer:
2x+6=-8(x>=-7), 2x+3<9(x<3), 2x-4<=-8(x<=-2), -x-8>=-5(x<=-3), x+-4<=-3(x<=1)
Step-by-step explanation:
Answer:
Where is the table
Step-by-step explanation:
I cant answer without it
Answer:
Step-by-step explanation:
I don’t know if this will help but I hope it does let me know if you get it or not
Answer:
14 days
Step-by-step explanation:
Amount earned by gardener for each day worked = $60
Amount paid by gardener for each day when absent = $15
Total number of days = 20
Let the total number of days when the gardener was working = x
Then he was absent for (20 - x) days.
Total amount earned during this period = $750
Then, ![\[60x - 15(20-x) = 750\] ](https://tex.z-dn.net/?f=%5C%5B60x%20-%2015%2820-x%29%20%3D%20750%5C%5D%0A)
=> ![\[60x + 15x - 300 = 750\]](https://tex.z-dn.net/?f=%5C%5B60x%20%2B%2015x%20-%20300%20%3D%20750%5C%5D)
=> \[75x = 1050\]
=> x = 14
So the gardener worked for 14 days out of 20.
