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3 years ago

area of the parallelogram

Mathematics

1 answer:

Jet001 [13]3 years ago

4 0

Answer:

48 $m^{2}$

Step-by-step explanation:

Area = base x height

Area = 8m x 6m

Area = $48m^{2}$

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If using the method of completing the square to solve the quadratic equation x^2-4x+10=0,which number would have to be added to

chubhunter [2.5K]

Answer:

Step-by-step explanation:

Given

x² - 4x + 10 = 0

subtract 10 from both sides

x² - 4x = - 10

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(- 2)x + 4 = - 10 + 4

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3 years ago

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jasenka [17]

Answer:

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2 years ago

Subtract the rational expression 1/x^2-x-6 - x/x+2.

Aleksandr [31]

Answer:

Step-by-step explanation:

x² - x -6 = x² + 2x - 3x - 3*2

=x(x + 2) - 3(x + 2)

= (x + 2 )(x - 3)

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$= \frac{1}{(x+2)(x-3)}-\frac{x(x-3)}{(x+2)(x-3)}\\\\=\frac{1-x(x-3)}{(x+2)(x-3)}\\\\=\frac{1-x^{2}+3x}{(x+2)(x-3)}\\\\$

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2 years ago

Help me please

kari74 [83]

Answer:

$\frac{ \cos(80) }{ \sin(10) } + \frac{ \sin(20) }{ \cos(70) } = 2 \\ \frac{ \cos(90 - 10) }{ \sin(10) } + \frac{ \sin(20) }{ \cos(9 0 - 20) } = 2 \\ \frac{ \sin(10) }{ \sin(10) } + \frac{ \sin(20) }{ \sin(20) } = 2 \\ 1 + 1 = 2 \\ 2 = 2 \\ \\ \frac{ \cot(40) }{ \tan(50) } + \frac{ \cos(65) }{ \sin(115) } = 2 \\ \frac{ \cot(90 - 50) }{ \tan(50) } + \frac{ \cos(65) }{ \sin(90 + 65) } = 2 \\ \frac{ \tan(50) }{ \tan(50) } + \frac{ \cos(65) }{ \cos(65) } = 2 \\ 1 + 1 \\ = 2$

6 0

3 years ago

What is the perimeter of the figure? A. 144 cm B. 76 cm C. 74 cm D. 45 cm

tatiyna

76 cm would be your answer, so B.

8 0

3 years ago

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￼area of the parallelogram

area of the parallelogram