A spinner has 5 equal sections numbered 1 to 5. What is the probability of the spinner stopping on a number that is a multiple o
1 answer:
Answer:
0.6
Step-by-step explanation:
Given that the spinner has 5 equal sections numbered 1 to 5.
- Total Sample Space, n(S)=5
Multiples of 2 in 1 to 5 are: {2,4}
Number less than than 3 are:{1,2}
Since we are required to find the probability of the spinner stopping on a number that is a multiple of 2 or is less than 3, we take the union of both sets.
{2,4} {1,2} ={1,2,4}
Number of Outcomes=3
Therefore,
Probability of the spinner stopping on a number that is a multiple of 2 or is less than 3
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The answer would be A.) 1
To find this answer you solve for x. Subtract 3/2 from both sides. This will give you 1/2x = 1/2^x. Then, divide by 1/2 on both sides to get x = 1.
To check this fill in x with 1. Then solve.
- 1/2 * 1/1 + 3/2 = 2^1
- 1/2 + 3/2 = 2
- 4/2 = 2
- 2 = 2
Thus making 1 the answer. Here's an image to show how I got this. I hope this helps!
