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Dahasolnce [82]
3 years ago
14

Peter scored 15 goals during his second soccer season as a forward. He scored 6 fewer goals during his first season. The team as

a whole scored 4 times as many goals as Peter during the two seasons. How many goals did the team score during the two seasons?
Mathematics
2 answers:
VikaD [51]3 years ago
5 0

Answer:

96 goals

Step-by-step explanation:

Take his 15 and subtract 6, which gives you nine. He scored 15 for the second and 9 the first season. Add 15 and 9 to get 24. Multiply 24 by 4 to get the total amount of goals scored by the team.

24×4=96

TEA [102]3 years ago
4 0

Answer:

The team scored 96 goals during the two seasons

Step-by-step explanation:

Let take Peter goal for the second season as x

And take Peter goal for the first season as y

And take the goal scored by the whole team for the two seasons as z

So.

X = 15 goals

Y = 15 - 6 goals

Y = 9goals

Z = 4(x+y)

Z = 4( 15 + 9)

Z = 4 (24)

Z = 96

Therefore the goal scored by the whole team for the two seasons is 96goals

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Andreyy89

Answer:

<u>The correct answer is B. {-2,4}</u>

Step-by-step explanation:

Let's solve for x, this way:

x + 4/4 = x /x -2

(x + 4) * ((x - 2) = 4 * x

x² - 2x + 4x -8 = 4x

x² - 2x + 4x -8 - 4x = 0

x² - 2x  -8 = 0

(x - 4) * (x +2) = 0

x - 4 = 0

x + 2 = 0

x₁ = 4

x₂ = - 2

<u>The correct answer is B. {-2,4}</u>

3 0
3 years ago
Diep bought a baguette loaf of bread 65 centimeters long. For lunch every afternoon, he cuts 15 centimeters of bread for his san
maxonik [38]
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Answer: x = -11   ∠FGK = 30°   ∠KGH = 150°

<u>Step-by-step explanation:</u>

∠FGK + ∠KGH = ∠FGH    <em>Segment Addition Postulate</em>

x + 41 + x + 161 = 180       <em>Substitution</em>

2x + 202 = 180  <em>               Simplify (added like terms)</em>

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x = -11                               <em>Division Property of Equality</em>

 

∠FGK = x + 41     = (-11) + 41    = 30

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7 0
3 years ago
Helppppp quick plz ​
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Answer:

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Step-by-step explanation:

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