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Pie
3 years ago
15

PLEASE HELP I BEG YOU

Mathematics
2 answers:
Montano1993 [528]3 years ago
7 0
Hello,
from left to right:

1) m=(5-0)/(0+3)=5/3

2) m=(0+3)/(-1+0)=-3

3) m=(0+4)/(6-0)=4/6=2/3

dangina [55]3 years ago
6 0
If you're finding slope, the answer is 5/3
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The angle between u = (-2,-5) and v = (5,2) is 134 degrees approximately.

<u>Solution:</u>

Given, two vectors are u = (-2, -5) and v = (5, 2)

We have to find the angle between two vectors.

We know that,

a. b=\|a\| .\|b\| \times \cos \theta

where \theta is angle between vectors a and b

\text { Now vectors are }(-2 \vec{\imath}-5 \vec{\jmath}) \text { and }(5 \vec{\imath}+2 \vec{\jmath})

(-2 \vec{\imath}-5 \vec{\jmath}) \cdot(5 \vec{\imath}+2 \vec{\jmath})=\sqrt{(-2)^{2}+(-5)^{2}} \times \sqrt{5^{2}+2^{2}} \times \cos \theta

\text { since }\|a\|=\sqrt{x^{2}+y^{2}} \text { for } a=x \vec{\imath}+y \vec{\jmath}

\begin{array}{l}{-10-10=\sqrt{29} \times \sqrt{29} \times \cos \theta} \\\\ {-20=29 \times \cos \theta} \\\\ {\cos \theta=\frac{-20}{29}} \\\\ {\theta=\cos ^{-1} \frac{-20}{29}} \\\\ {\theta=133.60}\end{array}

Hence, the angle between given two vectors is 134 degrees approximately.

3 0
3 years ago
How do I find the product when multiplying with decimals<br><img src="https://tex.z-dn.net/?f=0.36%20%5Ctimes%202.4" id="TexForm
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Step 1:

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now we can multiply the fractions

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multiplying numerator with numerator and denominator with denominator:

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Hope this helps you.

8 1
3 years ago
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babymother [125]

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