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2 years ago

What is the solution to the equation 88 = 8(v + 3)?

Mathematics

1 answer:

steposvetlana [31]2 years ago

5 0

Answer:

Step-by-step explanation:

8(v + 3) = 88

8v + 24 = 88

8v = 88 - 24 = 64

v =64/8 = 8

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AveGali [126]

Y=-3x+36 because the line crosses the y axis at 36

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2 years ago

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What are the potential solutions of In(x^2-25)=0?

Maslowich

Answer:

$x =\pm \sqrt{26}$

Step-by-step explanation:

Given :-

ln ( x² - 25 ) = 0

And we need to find the potential solutions of it. The given equation is the logarithm of x² - 25 to the base e . e is Euler's Number here. So it can be written as ,

Equation :-

$\implies log_e {(x^2-25)}= 0$

In general :-

If we have a logarithmic equation as ,

$\implies log_a b = c$

Then this can be written as ,

$\implies a^c = b$

In a similar way we can write the given equation as ,

$\implies e^0 = x^2 - 25$

Now also we know that $a^0 = 1$ Therefore , the equation becomes ,

$\implies 1 = x^2 - 25 \\\\\implies x^2 = 25 + 1 \\\\\implies x^2 = 26 \\\\\implies x =\sqrt{26} \\\\\implies x = \pm \sqrt{ 26}$

Hence the Solution of the given equation is ±√26.

6 0

2 years ago

An online furniture store sells chairs for $150 each and tables for $550 each. Every day, the store can ship a maximum of 40 pie

Katen [24]

Answer:

minimum of 13 chairs must be sold to reach a target of $6500

and a max of 20 chairs can be solved.

Step-by-step explanation:

Given that:

Price of chair = $150

Price of table = $400

Let the number of chairs be denoted by c and tables by t,

According to given condition:

t + c = 30 ----------- eq1

t(150) + c(400) = 6500 ------ eq2

Given that:

10 tables were sold so:

t = 10

Putting in eq1

c = 20 (max)

As the minimum target is $6500 so from eq2

10(150) + 400c = 6500

400c = 6500 - 1500

400c = 5000

c = 5000/400

c = 12.5

by rounding off

c = 13

So a minimum of 13 chairs must be sold to reach a target of $6500

i hope it will help you! mark me as brainliest pls

§ALEX§

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3 years ago

Directions: Find the missing wall in feet.

Sindrei [870]

Answer:

2.6?:))))

......

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2 years ago

At Norman's Newsstand, 5 magazines cost $20.00. How many magazines could you buy with $44.00?

kobusy [5.1K]

Answer: 11 magazines

Step-by-step explanation:

1) 20/5 = $4 per magazine

2) 44/4 = 11 magazines

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2 years ago

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