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3 years ago

What is the solution to the equation 88 = 8(v + 3)?

Mathematics

1 answer:

steposvetlana [31]3 years ago

5 0

Answer:

Step-by-step explanation:

8(v + 3) = 88

8v + 24 = 88

8v = 88 - 24 = 64

v =64/8 = 8

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Express the first number as a percentage of the second number. 29 pounds of recyclable trash in a barrel of 53 pounds of trash.

Rus_ich [418]

Divide first number by second number:

29 /53 = 0.54716981

Multiply by 100 to get percent:

0.54716981 x 100 = 54.716981%

Round the answer as needed.

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4 years ago

Which class has 28% boys?

Bas_tet [7]

Class D has 28% boys because 50 x 28% (or .28) you get 14

Hope this helps!

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3 years ago

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I have a $1.50. If I walk into a shop and I go to the checkout and in my shopping cart is a pack of chips that cost a $1.50 and

mixas84 [53]

Answer:

Step-by-step explanation:

I know you are not supposed to answer D, but it actually is a pretty good question to ask, perhaps of your teacher. Mathematically I don't really know what you should answer.

I don't think you should answer B. I'm certain this is an ethics question of some sort. What you are proposing with this answer is theft.

I don't think I'd buy the chips. My instincts would be to run out of the store.

I guess I'd pick C.

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3 years ago

Find the value of -2010/(-30)

Mekhanik [1.2K]

-2010 : (-30) = -201 : (-3) = 67

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3 years ago

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Suppose that 35 people are divided in a random manner into two teams in such a way that one team contains 10 people and the othe

Effectus [21]

Answer:

0.5798 or 57.98%

Step-by-step explanation:

The total number of ways to form the two teams is the combination of choosing 10 people out of 35 (₃₅C₁₀). The number of possibilities that A and B are both on the 10-people team is given by the combination of choosing 8 people (since two are fixed) out of 33 (₃₃C₈).The number of possibilities that A and B are both on the 25-people team is given by the combination of choosing 10 people out of 33 (₃₃C₈).

Therefore, the probability that two particular people A and B will be on the same team is:

$P = \frac{_{33}C_8+_{33}C_{10}}{_{35}C_{10}} \\\\P=\frac{\frac{33!}{(33-8)!8!}+\frac{33!}{(33-10)!10!} }{\frac{35!}{(35-10)!10!}} \\\\P=\frac{69}{119} = 0.5798$

The probability is 0.5798 or 57.98%.

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3 years ago