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Phoenix [80]
3 years ago
14

What is the factored form of this expression?

Mathematics
1 answer:
gayaneshka [121]3 years ago
7 0

Answer:

(x +  11 ) * ( x - 11)

Step-by-step explanation:

The expression:

x²   -    121

is a difference of squares

We notice that     √x²    =  x       and    √121    =   11

Then

( x²  -  121  )  =   ( x + 11 ) *  ( x  -  11 )

If we multiply

( x  +  11 ) *  ( x  -  11 )   =    x*x  - 11*x  +  11*x  - (11)*(11)

( x  +  11 ) *  ( x  -  11 )   =  x²  - 121

That is what we want to probe

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Which set of side lengths is a Pythagorean triple??? Please help
kodGreya [7K]

Answer:

C) 9,40,41

Step-by-step explanation:

Pythagorean triple is when a²+b²=c²

A) 1,3,10

  • 1+9=100 - incorrect

B) 4,5,9

  • 16+25=81- incorrect

C) 9,40,41

  • 81+1600= 1681- correct

D) 16,30,44

  • 256+900= 1936- incorrect
4 0
3 years ago
Expand the following x(x-6), x(4x-1), 2x(5x+4), 3x(5x-y)
zlopas [31]

Answer:

x^2-6x, 4x^2-1x,10x^2+8x,15x^2-3xy

Just use the distributive property like you have before and you will get these answers, Hope this helped!

4 0
3 years ago
Read 2 more answers
What number are 1.3 units from 0.4 on a number line
spayn [35]
0.5  ,0.6  ,0.7  ,0.8  ,0.9  ,1,1  .1  ,1.2  ,1.3

3 0
3 years ago
Read 2 more answers
If the perimeter is always 36 cm, how could you draw the rectangle so that it has the maximum area?
Romashka-Z-Leto [24]

Answer:

Draw it with 9 cm for length and width.

Step-by-step explanation:

The product is the maximum area when the length and width are as close as possible, or equal to each other. Because length and width are 2 sides each, we can divide 36 by 4, which is 9.

9x9 = 81 cm^2. This is the largest area possible.

4 0
3 years ago
An object is launched from a launching pad 208 ft. above the ground at a velocity of 192ft/sec. what is the maximum height reach
Alexeev081 [22]

Answer:

h(x) = -16x² + 192x + 208

784ft

6 sec

13 sec

Step-by-step explanation:

a)

h(x) = -16x² +vx + h_{o}

here v represent velocity

         h_{o} represent initial height of launch

       

h(x) = -16x² + 192x + 208

b)

h(x) = -16x² + 192x + 208

here a = -16

        b = 192

        c = 208

x = -b/2a

  = -192/2(-16)

  = 6

plug this value in the equation

h(x) = -16(6)² + 192(6) + 208

      = 784ft

e)

Plug h(x)=0 in the equation

0 = -16x² + 192x + 208

divide equation by -16

x² - 12x - 13 = 0

Factors

1x * -13x = -13

1x - 13x = -12

Factorised form

x² - 12x - 13 = 0

x² + x - 13x - 13 = 0

x(x+1) -13(x+1) = 0

(x+1)(x-13) = 0

x = -1

x = 13

Since time can not be negative so we will reject x = -1  

3 0
3 years ago
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