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alexgriva [62]
3 years ago
10

SS

Mathematics
1 answer:
Tanzania [10]3 years ago
8 0

Answer:

c = 160 - 3(45)

Step-by-step explanation:

if c = the number of characters left;

160 = maximum number of characters that can be used in a text

3*45 = number of characters in sentences already used. (There are 3 sentences of 45 characters.)

(# of char left) = (max # char) - (# char already used) so:

c = 160 - 3*(45)

c = 160 - 135

c = 25

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Are both 7 and -½ integers? why or why not?​
Tems11 [23]

Answer:

No. (-1/2) is not an integer

Integers involve all the no. +ve and -ve. which can be written without fraction. ie whole no. are counted as integers.

(-1/2) is a fraction

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2 years ago
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Julio separates his building blocks he draws a model to show how he separates his blocks . what division sentence does his model
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Were is the model????
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Find the prime factorization of each number.<br> 1. 50 =
Varvara68 [4.7K]

Answer:

1.5 is not a prime number

Step-by-step explanation:

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3 years ago
Consider the following hypothesis test. H0: μ ≥ 55 Ha: μ &lt; 55 A sample of 36 is used. Identify the p-value and state your con
Ket [755]

Answer:

Step-by-step explanation:

Given that:

H_o: \mu \ge 55 \ \\ \\ H_1 : \mu < 55

(a) For x = 54 and s = 5.3

The test statistics can be computed as:

Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }

Z = \dfrac{54-55}{\dfrac{5.3}{\sqrt{36}} }

Z = \dfrac{-1}{\dfrac{5.3}{6} }

Z = -1.132

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(-1.132,35,1) = 0.1326

Decision: p-value is greater than significance level; do not reject \mathbf{H_o}

Conclusion: \  There  \ is \  insufficient \  evidence  \  to \  conclude \  that \ \mu < 55

b

For x = 53 and s = 4.6

The test statistics can be computed as:

Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }

Z = \dfrac{53-55}{\dfrac{4.6}{\sqrt{36}} }

Z = \dfrac{-2}{\dfrac{4.6}{6} }

Z = -2.6087

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(-2.6087,35,1) =0.0066

Decision: p-value is < significance level; we reject the null hypothesis.

Conclusion: \  There  \ is \  sufficient \  evidence  \  to \  conclude \  that \mu < 55

c)

For x = 56 and s = 5.0

The test statistics can be computed as:

Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }

Z = \dfrac{56-55}{\dfrac{5.0}{\sqrt{36}} }

Z = \dfrac{56-55}{\dfrac{5.0}{\sqrt{36}} }

Z = 1.2

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(1.2,35,1) = 0.88009

Decision: p-value is greater than significance level; do not reject \mathbf{H_o}

Conclusion: \  There  \ is \  insufficient \  evidence  \  to \  conclude \  that \ \mu < 55

6 0
3 years ago
Find the vertex.<br> f(x) = x2 + 3
Musya8 [376]

Answer:

(0,3)

Step-by-step explanation:

The parent function's vertex is at (0,0) and this function is being translated 3 units up, so the vertex is at (0,3)

4 0
3 years ago
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