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777dan777 [17]
3 years ago
7

Find the inverse of the following function.

Mathematics
1 answer:
Naddik [55]3 years ago
3 0

For this case we must find the inverse of the following function:

f (x) = 8 \sqrt {x}

For this, we follow the steps below:

We change f (x) to y:

y = 8 \sqrt {x}

We exchange the variables:

x = 8 \sqrt {y}

We solve for y:

8 \sqrt {y} = x

We divide between 8 on both sides of the equation:

\sqrt {y} = \frac {x} {8}

We raise both sides of the equation to the square to remove the root:

y = (\frac {x} {8}) ^ 2\\y = \frac {x ^ 2} {64}

So, the inverse is:f ^ {- 1} (x) = \frac {x ^ 2} {64}

ANswer:

Option C

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3 years ago
I just need answers to the odd numbered questions.<br> I would appreciate the help<br><br> 35 points
Misha Larkins [42]

Answer:

Step-by-step explanation:

Combine real terms and combine complex terms

1) 3 + 2i + 2 - 5i = 3 +2 + 2i - 5i

                          = 5 + (2-5)i

                          = 5 + (-3)i

                          = 5 - 3i

3) 2 - (1 - 2i) + (4 -5i ) - (1 - 3i)  = 2 -1 + 2i + 4 - 5i - 1 + 3i

           {- is distributed to (1 - 2i) & - is distributed to (1- 3i)}

              = 2 - 1  + 4 + 1 + 2i - 5i + 3i

              = 6 +0i = 6

5) 4 - 3i + 4 + 3i = 4 +4 -3i + 3i

                          = 8

7) (3 - 2i)² + (3 +2i) = 3² - 2*3*2i + (2i)² + 3 + 2i     {(a - b)² = a² - 2ab +b²}

= 9 -12i + 4i² + 3 + 2i

= 9 - 12i + 4*(-1) + 3 + 2i       {i²  = -1}

= 9 +3 - 4 - 12i +2i

= 8 - 10i

9) (a +b)^{4} - (a - b)^{4} = 8ab(a^{2} +b^{2})\\\\\\Here, \ a = 1 \ and \ b = i\\\\\\(1+\sqrt{-1})^{4}-(1-\sqrt{-1})^{4}=(1+\sqrt{i^{2}})^{4}-(1-\sqrt{i^{2}})^{4}\\\\=(1+i)^{4}-(1-i)^{4}\\\\=8*1*i(1^{2}+i^{2})\\\\=8i*(1 -1)\\\\=8i*0\\\\=0

6 0
3 years ago
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