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Flura [38]
3 years ago
11

The near point (the smallest distance at which an object can be seen clearly) and the far point (the largest distance at which a

n object can be seen clearly) are measured for six different people.
near far
point point
(cm) (cm)
Avishka 40 ?
Berenice 30 300
Chadwick 25 500
Danya 25 ?
Edouard 80 200
Francesca 50 ?
A) Which, if any of these people are nearsighted (myopic)?
B) Which, if any, of these people require bifocals to correct their vision?
C) Which, if any, of these people's vision can be corrected using only converging lenses?
Physics
1 answer:
Mekhanik [1.2K]3 years ago
3 0

Answer:

Edouard> Francesca> Avishka> Berenice> Chanwick> Danya

Para el point of the far vision  (hyperopic)

Edouard > Berenica  > Chdwick > Francesca =  Avishka = Danya

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A 110 kg ice hockey player skates at 3.0 m/s toward a railing at the edge of the ice and then stops himself by grasping the rail
velikii [3]

Answer:

Δ KE = -495 J

Explanation:

given,

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final speed  = 0 m/s

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change in kinetic energy

\Delta K E = \dfrac{1}{2}mv_f^2 - \dfrac{1}{2}mv_i^2

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4 0
3 years ago
If Vx = 7.00 units and Vy = -7.60 units, determine the magnitude of V⃗ .
Juliette [100K]

|V| = 10.33 units and the direction θ = -47.35° or 312.65°.

Given the x and y components of a vector, we can calculate the magnitude and direction from these components.

Applying the Pythagorean theorem we have that the magnitude of the vector is:

|V| = \sqrt{Vx^{2}+Vy^{2}  }

|V| = \sqrt{(7.00units)^{2}+(-7.60units)^{2}} = \sqrt{106units^{2}} = 10.33units

The expression for the direction of a vector comes from the definition of the tangent of an angle:

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θ = -47.35° or 312.65°

6 0
3 years ago
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