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igomit [66]
4 years ago
10

Express as functions of positive acute angles:

Mathematics
1 answer:
prisoha [69]4 years ago
4 0
1. Sin 240 degree = -sin ( 240 -180 degree) = -sin (60 degree)
2. Tan 130 degree = -tan ( 180 - 130 degree) = -tan 50 degree
3. sec 305 degree = sec ( 360 - 305 degree) = sec (55 degree)
4. cos 95 degree = -<span>cos (180 - 95 degree ) = -cos 85 degree</span>
5. csc 185 degree = -sin 5 degree
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Which planet is about 1 /10 of the distance Uranus is from the sun?
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There is no real planet that is 1/10 the distance Uranus is from the sun, however the planetoid (smaller planet), Vesta is 1/9 the distance Uranus is from the sun.
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3 years ago
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Which of these represents an integer? Select all that apply. (There should be two anwsers) A. -3 B. 4 C. 2 1/2 D. 8/4
Sladkaya [172]
A.-3, B.4; the definition of integer is a who number. Fractions are not whole numbers (the fractions in choice C and D) while fractions are not whole numbers, negative numbers are still numbers.
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4 years ago
Given the graph of a function below, Determine the interval in which the function has a negative value.
Serggg [28]

Answer:

B

Step-by-step explanation:

The "value" of a function is the y-value.

Since we want negative y values, we look at "WHERE" the function is "UNDER" the y-axis.

Looking closely, it looks that function (the dip) is from x = -1 to x = 3

Hence, the function is negative at the interval  -1 ≤ x ≤ 3

B is correct.

8 0
4 years ago
Unfortunately, arsenic occurs naturally in some ground water†. A mean arsenic level of μ = 8.0 parts per billion (ppb) is consid
riadik2000 [5.3K]

Answer:

t=\frac{7.2-8}{\frac{2.1}{\sqrt{41}}}=-2.439    

p_v =P(t_{(40)}  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and the true mean is lower than 8 ppb at 1% of signficance. We need to be careful with this interpretation since the p value is near to the significance level.  

Step-by-step explanation:

Data given and notation  

\bar X=7.2 represent the mean height for the sample  

s=2.1/tex] represent the sample standard deviation [tex]n=41 sample size  

\mu_o =8 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is less than 8, the system of hypothesis would be:  

Null hypothesis:\mu \geq 8  

Alternative hypothesis:\mu < 8  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{7.2-8}{\frac{2.1}{\sqrt{41}}}=-2.439    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=41-1=40  

Since is a one side test the p value would be:  

p_v =P(t_{(40)}  

Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and the true mean is lower than 8 ppb at 1% of signficance. We need to be careful with this interpretation since the p value is near to the significance level.  

4 0
4 years ago
Solving the equation:-9h-6+ 12h +40=20
MakcuM [25]
12h-9h=3h move everything else to other side
3h=20-40+6
3h=-14
divide by 3 
h=-14/3
5 0
3 years ago
Read 2 more answers
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