1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Whitepunk [10]
2 years ago
15

Answer for brainlest

Mathematics
2 answers:
jonny [76]2 years ago
5 0

Answer:

∠1 = ∠8

Step-by-step explanation:

Because alternate exterior angles are equal.

Also there is no angle given so you cant work them out.

simply put:

∠1 = ∠8

∠1 = ∠4

∠3 = ∠2

∠1 = ∠5

∠2 = ∠6

∠2 = ∠7

∠5 = ∠8

∠4 = ∠8

∠7 = ∠6

∠7 = ∠3

Let me know if I missed out on anymore! It was long that's why.

Hope this kind of explained it :)

vladimir1956 [14]2 years ago
3 0

Answer:

∠1 = ∠8

Step-by-step explanation:

Because they are ALTERNATE EXTERIOR ANGLE

You might be interested in
Find the volume of the cone. Round your answer to the nearest tenth.
oee [108]

Answer:

15205.3  

Step-by-step explanation: H=30  R²=484  3.14=π  →= rounded up to tenth  V = Volume

<em><u>formula (no numbers): H x R² x π ÷</u></em><u> </u>\frac{1}{3}<u> (or 3) </u><em><u>= V</u></em>

<u><em>how i got the answer :  30 x 484 x 3.14 ÷ 3 = 15205.31  → 15205.3</em></u>

4 0
2 years ago
Help! Find m^KNL.<br> A. 264<br> B. 196<br> C. 184<br> D. 247
Misha Larkins [42]

Answer:

  A.  264

Step-by-step explanation:

First, we have to find the value of x. Then we can use that to find the required arc measure.

∠M = (1/2)(arc KN - arc LN)

60 = (1/2)((18x -6) -(5x +17)) = (1/2)(13x -23) . . . . substitute and simplify

120 = 13x -23 . . . . . . . multiply by 2

143 = 13x . . . . . . . . . . add 23

11 = x . . . . . . . . . . . . . . divide by 13

__

arc KNL = (arc KN) + (arc NL) = (18x -6) +(5x +17) = 23x +11

  = 23·11 +11

arc KNL = 264 . . . . degrees

5 0
3 years ago
Which of the following is not true about cluster sampling?
Aloiza [94]

Answer:

The correct answer is D. It is not true that cluster sampling uses randomly selected clusters and samples everyone within each cluster.

Step-by-step explanation:

Cluster sampling is a method of collecting samples and statistical data, by means of which a certain group formed by people, things, events, etc., is taken as a sample, which are not considered individually but as part of a whole, which is in turn a proportional representation of the universality of samples available in the field.

Now, since this type of sampling allows to embrace large groups of sample units, data are not always obtained from all the components of the cluster, but from those necessary to be able to quantify the desired statistics.

5 0
2 years ago
Read 2 more answers
Kate paid $27 for a dress that was on sale at 10% off. What was the original price for this dress?
wolverine [178]
Hope u understand...

4 0
3 years ago
Read 2 more answers
Use the regression calculator to compare the teams’ number of runs with their number of wins.
Yanka [14]

Answer:

-23.21

Step-by-step explanation:

Edge 2021

5 0
2 years ago
Read 2 more answers
Other questions:
  • If the complex number x = 3 + bị and x/2 = 13, which is a possible value of b?
    9·1 answer
  • The problem has too little information:
    7·2 answers
  • What is the slope of the line that passes through the points (1, -6)(1,−6) and (-8, 9) ?(−8,9)?
    11·1 answer
  • Write the equation of the line that is parallel to y=1/4x+5 and passes through (2,-9)
    9·1 answer
  • Pls help fast 25 points! 60% of 45 =
    12·2 answers
  • 6.The perimeter of a rectangle whose length is 7.5cm and breadth 3.75cm​
    14·2 answers
  • Can you guys please help me
    6·1 answer
  • If your favorite grass blade gets stuck in the microwave and your arms are too long to grab it, how many colors of the day July
    9·2 answers
  • Solve each system by elimination.<br><br> -9x + 4y = 7<br> -2x-4y=-18
    13·2 answers
  • Which relation is a function?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!